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anygoal [31]
4 years ago
6

Remove the positive charge by dragging it back to the box at the bottom, and drag a negative charge (blue) toward the middle of

the screen.
Determine how the electric field is different from that of the positive charge.
What statement best describes the differences in the electric field due to a negative charge as compared to a positive charge?
Physics
1 answer:
Alik [6]4 years ago
7 0

Answer:

the Voltages become negative instead of positive but the magnitude remains the same.

Explanation:

If we remove  the positive charge by dragging it back to the box at the bottom, and drag a negative charge (blue) toward the middle of the screen, the Voltages become negative instead of positive but the magnitude remains the same.

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The figure shows a velocity-versus-time graph for a particle moving along the x-axis. At t=0s, assume that x=0m. What is the par
swat32

Using the velocity-time graph, the displacement can be calculated by the area under the velocity-time graph. At 3 seconds the total displacement is then equal to (4)(2) + (4 + 2)*1/2 = 11 m. Assuming that the starting point is at x = 0, then the particle at t=3s is at x=11 m.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
7 0
3 years ago
What force causes a rolling ball to slow down and stop
MAXImum [283]
Newtons first law of motion or friction
3 0
3 years ago
Read 2 more answers
An upward force act on a proton as it moves with a speed of 2.0 x 10^5 meters/seconds through a magnetic field of 8.5 x 10^2
Gekata [30.6K]

Force on a moving charge is given by formula

\vec F = q(\vec v \times \vec B)

here we know that this force will be maximum when velocity is perpendicular to magnetic field

\vec F = qvB

here we know that

v = 2.0 \times 10^5 m/s

q = 1.6 \times 10^{-19} C

B = 8.5 \times 10^2 T

now we have

F = (1.6 \times 10^{-19})(2 \times 10^5)(8.5 \times 10^2)

F = 2.72 \times 10^{-11} N

7 0
3 years ago
You have a horizontal cathode ray tube (CRT) for which the controls have been adjusted such that the electron beam should make a
Dvinal [7]

Answer:

Explanation:

Rotate it slowly to establish whether the spot moves. If it is broken, it will stay as it is. By rotating it the electrons' path to the centre of the screen will be tilted to another position by any external disturbing field.

8 0
3 years ago
2. A can filled with sand has a mass of 0.65kg is swung overhead in a horizontal circle of radius 0.70m at a constant rate of 2.
Aliun [14]
<h3><u>Answer</u>;</h3>

≈ 5 Kgm²/sec

<h3><u>Explanation</u>;</h3>

Angular momentum is given by the formula

L = Iω, where I is the moment of inertia and ω is the angular speed.

I = mr², where m is the mass and r is the radius

 = 0.65 × 0.7²

 = 0.3185

Angular speed, ω = v/r

                              = (2 × 3.142 × r × 2.5) r

                              =  15.71

Therefore;

Angular momentum =  Iω

                                 = 0.3185 × 15.71

                                 = 5.003635

                                 <u>≈ 5 Kgm²/sec</u>

6 0
3 years ago
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