Answer: E = 39.54 N/C
Explanation: Electric field can be determined using surface charge density:
![E = \frac{\sigma}{2\epsilon_{0}}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B%5Csigma%7D%7B2%5Cepsilon_%7B0%7D%7D)
where:
σ is surface charge density
is permitivitty of free space (![\epsilon_{0} = 8.85.10^{-12}](https://tex.z-dn.net/?f=%5Cepsilon_%7B0%7D%20%3D%208.85.10%5E%7B-12%7D)
)
Calculating resulting electric field:
![E=E_{1} - E_{2}](https://tex.z-dn.net/?f=E%3DE_%7B1%7D%20-%20E_%7B2%7D)
![E = \frac{\sigma_{1}-\sigma_{2}}{2\epsilon_{0}}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B%5Csigma_%7B1%7D-%5Csigma_%7B2%7D%7D%7B2%5Cepsilon_%7B0%7D%7D)
![E = \frac{[0.3-(-0.4)].10^{-9}}{2.8.85.10^{-12}}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B%5B0.3-%28-0.4%29%5D.10%5E%7B-9%7D%7D%7B2.8.85.10%5E%7B-12%7D%7D)
![E=0.03954.10^{3}](https://tex.z-dn.net/?f=E%3D0.03954.10%5E%7B3%7D)
E = 39.54
The resulting Electric Field at any point is 39.54N/C.
Answer:
D
Explanation:
The north field of a magnet is the positive side. Arrows pointing out of a side = positive
Let at any instant of time the speed is vo and the angle made by the bike with the horizontal is given
now we have
component of speed in x direction given as
![v_x = v_0cos\theta](https://tex.z-dn.net/?f=v_x%20%3D%20v_0cos%5Ctheta)
component of speed in y direction will be
![v_y = v_0sin\theta](https://tex.z-dn.net/?f=v_y%20%3D%20v_0sin%5Ctheta)
now from above two equations we can say that here
= angle with the horizontal at any instant
and since here it is a sine curve so we know that
![y = sin(x)](https://tex.z-dn.net/?f=y%20%3D%20sin%28x%29)
so we have slope of graph
![tan\theta = \frac{dy}{dx} = cos(x)](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D%20cos%28x%29)
T = ??°K, V = 15.50L, P = 870torr
PV = nRT, with P in atm, 760torr/atm
T = PV / nR = 1atm/760torr × 870torr×15.5 ÷ .0821 = 216.12 °K
Answer:
![E=7.28\times 10^6\ J](https://tex.z-dn.net/?f=E%3D7.28%5Ctimes%2010%5E6%5C%20J)
Explanation:
Given that,
Mass of a person, m = 84 kg
The person is standing at a top of Mt. Everest at an altitude of 8848 m
We need to find the gravitational potential energy of the person. We know that the gravitational potential energy is possessed due to the position of an object. It is given by :
E = mgh, g is the acceleration due to gravity
![E=84\ kg\times 9.8\ m/s^2\times 8848\ m\\\\E=7283673.6\ J\\\\E=7.28\times 10^6\ J](https://tex.z-dn.net/?f=E%3D84%5C%20kg%5Ctimes%209.8%5C%20m%2Fs%5E2%5Ctimes%208848%5C%20m%5C%5C%5C%5CE%3D7283673.6%5C%20J%5C%5C%5C%5CE%3D7.28%5Ctimes%2010%5E6%5C%20J)
So, the gravitational potential energy of the person is ![7.28\times 10^6\ J](https://tex.z-dn.net/?f=7.28%5Ctimes%2010%5E6%5C%20J)