The electric flux on a surface of area A in a uniform electric field E is given by
φ = EA cos θ
where θ = the angle between the directions of E and a normal vector to the surface of the area.
See the diagram shown below.
When the electric field is perpendicular to the surface, then θ = 0°, and
φ = EA cos(0°) = (6.20 x 10⁵ N/C)*(3.2 m²) = 1.984 x 10⁶ (N-m²)/C
When the electric field is parallel to the area, then θ = 90°, and
φ = EA cos(90°) = 0
Answer:
(a) 1.984 x 10⁶ (N-m²)/C
(b) 0
Because the average of one measurement would yield to itself, which provides nothing new to us. We need at least two for average to be purposeful.
Answer:
330Ns
Explanation:
Given parameters:
Mass of the box = 5kg
Initial velocity = 0m/s
Force applied = 15N
Time = 22s
Unknown:
Impulse = ?
Final momentum = ?
Solution:
The impulse of the box can be determined using the expression below:
Impulse = Force x time
Impulse = 15 x 22 = 330Ns
The final momentum is the same as this impulse
The impulse and the final momentum is 330Ns
Statements A, B, and C are true.
Statement <em> D is false</em>.