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3 years ago

Magnesium chloride forms crystals. Which option is a description of this

Physics

2 answers:

shtirl [24]3 years ago

4 0

The answer is B. This form of magnesium chloride is not a liquid but a solid that is white and colorless.

telo118 [61]3 years ago

3 0

Answer:

B) A solid made up of a highly organized set of particles

Explanation:

A.P.E.X

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A non-conducting sphere of radius R = 3.0 cm carries a charge Q = 2.0 mC distributed uniformly throughout its volume. At what di

BlackZzzverrR [31]

Answer:

$r =3 *\sqrt{2} = 4.24 cm$

Explanation:

given data

Radius of sphere 3.0 cm

charge Q = 2.0 m C

We know that maximum electric field is given as

$E_{MAX}= \frac{KQ}{r^{2}}$

electric field inside the sphere can be determine by using below relation

$\frac{KQ}{r^{2}}= \frac{1}{2}*\frac{KQ}{R^{2}}$

$r = \sqrt{2}R$

$r =3 *\sqrt{2} = 4.24 cm$

4 0

3 years ago

Branches of sicence

Sonja [21]

Answer:

physical science

earth science and life science

5 0

2 years ago

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Could a person at the south pole see the north star, explain??

9966 [12]

Answer:

If conditions are just right, you can see Polaris from just south of the equator. Although Polaris is also known as the North Star, it doesn't lie precisely above Earth's North Pole. If it did, Polaris would have a declination of exactly 90 degree.

Explanation:

4 0

2 years ago

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If the charges attracting each other in the preceding problem have equal magnitudes,show that the magnitude of each charge is 2.

Schach [20]

Answer:

The magnitude of each charge is $2.82\times10^{-6}\ C$

Explanation:

Suppose the two point charges are separated by 6 cm. The attractive force between them is 20 N.

We need to calculate the magnitude of each charge

Using formula of force

$F=\dfrac{kq^2}{r^2}$

Where, q = charge

r = separation

Put the value into the formula

$20=\dfrac{9\times10^{9}\times q^2}{(6\times10^{-2})^2}$

$q^2=\dfrac{(6\times 10^{-2})^2\times20}{9\times10^{9}}$

$q=\sqrt{\dfrac{(6\times 10^{-2})^2\times20}{9\times10^{9}}}$

$q=2.82\times10^{-6}\ C$

Hence, The magnitude of each charge is $2.82\times10^{-6}\ C$

6 0

3 years ago

Photoelectrons are observed when a metal is illuminated by light with a wavelength less than 383 nm. What is the metal's work fu

Ulleksa [173]

Answer:

Work function of the metal is 3.24 eV.

Explanation:

It is given that,

Wavelength, $\lambda=383\times 10^{-9}\ m$

Let W is the work function of the metal. It is given by using Einstein's photoelectric effect equation. It is given by :

$W=\dfrac{hc}{\lambda}$

$W=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{383\times 10^{-9}}$

$W=5.193\times 10^{-19}\ J$

Since, $1\ eV=1.6\times 10^{-19}\ J$

So, W = 3.24 eV

So, the work function of the metal is 3.24 eV. Hence, this is the required solution.

3 0

2 years ago

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