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3 years ago

2. A metal weighing 50.0 g absorbs 220.0 J of heat when its temperature increases by

Physics

1 answer:

zepelin [54]3 years ago

7 0

The specific heat of the metal is $0.037 J(g^{\circ}C)$

Explanation:

When a sample of a material absorbs energy, its temperature increases according to the equation

$Q=m C_s \Delta T$

where

Q is the amount of energy supplied to the sample

m is the mass of the sample

Cs is its specific heat capacity

$\Delta T$ is the increase in temperature

In this problem,

m = 50.0 g

Q = 220.0 J

$\Delta T =120.0^{\circ}C$

Solving for C_s, we find the specific heat capacity:

$C_s = \frac{Q}{m\Delta T}=\frac{220.0}{(50.0)(120.0)}=0.037 J(g^{\circ}C)$

Learn more about specific heat capacity:

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Consider a rifle, which has a mass of 2.44 kg and a bullet which has a mass of 150 grams and is loaded in the firing chamber.Whe

svetlana [45]

Answer:

a. 0 kgm/s

b. 0 kgm/s

c. 66 kgm/s

d. -66 kgm/s

e. 0 kgm/s

f. -27.05 m/s

g. 173.68 N

h. 12.58 m/s

i. 0.772 m

j. 14487 J

Explanation:

150 g = 0.15 kg

a. Before the bullet is fired, both rifle and the bullet has no motion. Therefore, their velocity are 0, and so are their momentum.

b. The combination is also 0 here since the bullet and the rifle have no velocity before firing.

c. After the bullet is fired, the momentum is:

0.15*440 = 66 kgm/s

d. As there's no external force, momentum should be conserved. That means the total momentum of both the bullet and the rifle is 0 after firing. That means the momentum of the rifle is equal and opposite of the bullet, which is -66kgm/s

e. 0 according to law of momentum conservation.

f. Velocity of the rifle is its momentum divided by mass

v = -66 / 2.44 = -27.05 m/s

g. The average force would be the momentum divided by the time

f = -66 / 0.38 = 173.68 N

h. According the momentum conservation the bullet-block system would have the same momentum as before, which is 66kgm/s. As the total mass of the bullet-block is 5.1 + 0.15 = 5.25. The velocity of the combination right after the impact is

66 / 5.25 = 12.58 m/s

i. The normal force and also friction force due to sliding is

$F_f = N\mu = Mg\mu = 5.25*9.81*0.83 = 42.75N$

According to law of energy conservation, the initial kinetic energy will soon be transformed to work done by this friction force along a distance d:

$W = K_e$

$dF_f = 0.5Mv_0^2$

$d = \frac{Mv_0^2}{2F_f} = \frac{5.25*12.58^2}{2*42.75} = 0.772 m$

j.Kinetic energy of the bullet before the impact:

$K_b = 0.5*m_bv_b^2 = 0.5*0.15*440^2 = 14520 J$

Kinetic energy of the block-bullet system after the impact:

$K_e = 0.5Mv_0^2 = 0.5 * 5.25*12.58^2 = 33 J$

So 14520 - 33 = 14487 J was lost during the lodging process.

3 0

3 years ago

A wave travels a distance of 60cm in 3s. The distance blw successive crests of thd wave is 4cm. What is the frequency?

schepotkina [342]

Data:
ΔS = 60cm
Δt = 3s
Vm = ?

Vm = ΔS/Δt
$Vm = \frac{60}{3}$
$Vm = 20cm/s$

We have:

Vm = v
ΔS = λ
Δt = T

$v = \frac{\lambda}{T}$
$20 = \frac{\lambda}{4}$
$\lambda = 20*4$
$\lambda = 80cm$

Soon:

$v = \lambda*f$
$20 = 80*f$
$80f = 20$
$f = \frac{20}{80} simplify( \frac{\div20}{\div20} )= \frac{1}{4}$
$\boxed{f = 0,25Hz}$

6 0

3 years ago

4. A net force of 15 N is exerted on a book to cause it to accelerate at a rate of 5 m/s2. Determine the mass of the

kenny6666 [7]

Answer:

Explanation:

The mass of an object given it's force and acceleration can be found by using the formula

$m = \frac{f}{a} \\$

f is the force

a is the acceleration

From the question we have

$m = \frac{15}{5} = 3 \\$

We have the final answer as

Hope this helps you

4 0

2 years ago

Scientists are studying a group of living cells under a microscope. They write down notes about the size, shape, and color of th

Lilit [14]

Answer:

Explanation:

descriptive, because scientists are writing down the observations but not making comparisons.

3 0

2 years ago

Explain the relationship of charles law to absolute zero

vivado [14]

Chalres law and absolute zero . in 1780s, by experiments

8 0

3 years ago