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Sunny_sXe [5.5K]
3 years ago
6

Look at the periodic table. Find the element carbon. What is its symbol?

Chemistry
2 answers:
Sliva [168]3 years ago
6 0
A. ca is the answer because its short for carbon
VMariaS [17]3 years ago
6 0
THE ANSWER IS B. C
if you have a question like that just google it because the answer pops up really quick
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Where can fire might be used as a management tool ?
lions [1.4K]
Natural vegetation!!

8 0
3 years ago
What is the volume of 15.2 grams of SO2 at STP?
kiruha [24]

5.512 litres is the volume of  15.2 grams of sulphur dioxide gas at STP.

Explanation:

Data given:

mass of sulphur dioxide = 15.2 grams

conditions is at STP whech means volume = 22.4 litres

atomic mass of sulphur dioxide = 64.06 grams/mole

Number of moles is calculated as:

number of moles = \frac{mas}{atomic mass of 1 mole}

Putting the values in the equation:

number of moles = \frac{15.2}{64.06}

                              = 0.23 moles

Assuming that sulphur dioxide behaves as an ideal gas, we can calculate the volume as:

When 1 mole of sulphur dioxide occupies 22.4 litres at STP

Then 0.23 moles of sulphur dioxide occupies 22.4 x 0.23

= 5.152 litres is the volume.

5 0
3 years ago
When the concentration of A in the reaction A ..... B was changed from 1.20 M to 0.60 M, the half-life increased from 2.0 min to
Reika [66]

Answer:

2

0.4167\ \text{M}^{-1}\text{min}^{-1}

Explanation:

Half-life

{t_{1/2}}A=2\ \text{min}

{t_{1/2}}B=4\ \text{min}

Concentration

{[A]_0}_A=1.2\ \text{M}

{[A]_0}_B=0.6\ \text{M}

We have the relation

t_{1/2}\propto \dfrac{1}{[A]_0^{n-1}}

So

\dfrac{{t_{1/2}}_A}{{t_{1/2}}_B}=\left(\dfrac{{[A]_0}_B}{{[A]_0}_A}\right)^{n-1}\\\Rightarrow \dfrac{2}{4}=\left(\dfrac{0.6}{1.2}\right)^{n-1}\\\Rightarrow \dfrac{1}{2}=\left(\dfrac{1}{2}\right)^{n-1}

Comparing the exponents we get

1=n-1\\\Rightarrow n=2

The order of the reaction is 2.

t_{1/2}=\dfrac{1}{k[A]_0^{n-1}}\\\Rightarrow k=\dfrac{1}{t_{1/2}[A]_0^{n-1}}\\\Rightarrow k=\dfrac{1}{2\times 1.2^{2-1}}\\\Rightarrow k=0.4167\ \text{M}^{-1}\text{min}^{-1}

The rate constant is 0.4167\ \text{M}^{-1}\text{min}^{-1}

3 0
3 years ago
The penguin has a ___ body that helps it to move quickly in water.
Lerok [7]
The penguin has a sleek body that helps it to move quickly in water.
7 0
3 years ago
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How many cm 3 are in 0.14 m 3?
nlexa [21]

Answer:

There are 14 cm in 0.14 m

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