Answer:
The magnitude of the horizontal displacement of the rock is 7.39 m/s.
Explanation:
Given that,
Initial speed = 11.5 m/s
Angle = 50.0
Height = 30.0 m
We need to calculate the horizontal displacement of the rock
Using formula of horizontal component

Put the value into the formula


Hence, The magnitude of the horizontal displacement of the rock is 7.39 m/s.
Answer:
1923 N
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 65 Kg
Radius (r) = 2.5 m
Velocity (v) = 8.6 m/s
Centripetal force (F) =?
The centripetal force, F, can be obtained by using the following formula:
F = mv²/r
F = 65 × 8.6² / 2.5
F = 65 × 73.96 / 2.5
F = 4807.4 / 2.5
F = 1922.96 ≈ 1923 N
Thus, the magnitude of the centripetal's force acting on the student is approximately 1923 N
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Answer:
63.9 m/s
Explanation:
Parameters given:
Mass of small car, m = 1200 kg
Mass of SUV, M = 4000 kg
Speed of SUV, V = 35 m/s
Their kinetic energy of the small car is equal to the kinetic energy of the SUV, hence:
0.5 * m * v² = 0.5 * M * V²
=> 0.5 * 1200 * v² = 0.5 * 4000 * 35²
600 * v² = 2450000
v² = 2450000/600
v² = 4083.3
=> v = 63.9 m/s
The speed of the small car is 63.9 m/s.
Answer:
9.21954 m/s
54 m/s²
Angle is zero
Explanation:
r = Radius of arm = 1.5 m
= Angular velocity = 6 rad/s
The horizontal component of speed is given by

The vertical component of speed is given by

The resultant of the two components will give us the velocity of hammer with respect to the ground

The velocity of hammer relative to the ground is 9.21954 m/s
Acceleration in the vertical component is zero
Net acceleration is given by

Net acceleration is 54 m/s²
As the acceleration is towards the center the angle is zero.