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100 POINTS ANSWER HURRY

prisoha [69]

C. Not all mixtures have solutes and solvents

7 0

4 years ago

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Calculate the number of grams of solute in 500.0 mL of 0.189 M KOH.

KIM [24]

Answer : The number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams

Solution : Given,

Volume of solution = 500 ml

Molarity of KOH solution = 0.189 M

Molar mass of KOH = 56 g/mole

Formula used :

$Molarity=\frac{\text{Mass of KOH}\times 1000}{\text{Molar mass of KOH}\times \text{Volume of solution in ml}}$

Now put all the given values in this formula, we get the mass of solute KOH.

$0.189M=\frac{\text{Mass of KOH}\times 1000}{(56g/mole)\times (500ml)}$

$\text{Mass of KOH}=5.292g$

Therefore, the number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams

7 0

3 years ago

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Make an observation about the average height of the beanbag for each mass dropped. How does it compare with your calculated kine

Gekata [30.6K]

Answer:

the other person is correct

Explanation:

3 0

3 years ago

What is the difference between polar and non-polar

ExtremeBDS [4]

Answer:

Polar molecules occur when there is an electronegativity difference between the bonded atoms. Nonpolar molecules occur when electrons are shared equal between atoms of a diatomic molecule or when polar bonds in a larger molecule cancel each other out.

Explanation:

Polar molecules occur when there is an electronegativity difference between the bonded atoms. Nonpolar molecules occur when electrons are shared equal between atoms of a diatomic molecule or when polar bonds in a larger molecule cancel each other out.

5 0

3 years ago

A patients blood is tested for growth hormone which has a molecular mass of 848.952g/mol. The test results show a normal concent

rusak2 [61]

Answer:

$\boxed{4.7\times 10^{-9}}$

Explanation:

Data:

MM = 848.952 g/mol

c = 4.0 x 10⁻⁶ g/L

V = 1 L

Calculations:

(a) Mass of growth hormone

$\text{Mass} = \text{1 L} \times \dfrac{4.0 \times 10^{-6} \text{ g}}{\text{1 L}} = 4.0 \times 10^{-6} \text{ g}$

(b) Moles of growth hormone

$\text{Moles} = 4.0 \times 10^{-6} \text{ g} \times \dfrac{\text{1 mol}}{\text{848.952 g}} = 4.7\times 10^{-9}\text{ mol}\\\\\text{There are $\boxed{\mathbf{4.7\times 10^{-9}}\textbf{ mol}}$ of growth hormone in 1 L of blood.}$

8 0

4 years ago