Answer:
When the electric field due to one is a maximum, the electric field due to the other is also a maximum, and this relation is maintained as time passes.
Explanation:
Phase of a wave or light ray is the instantaneous situation of the cycle in which the wave is at a given time.
When two waves are in phase means that the maximum and minimum of both coincide in time. They are in the same point of their cycle at the same time. And this relationship is maintained as time passes.
The waves can also be visualized as the oscillation of an electric field. (usually plotted like a sine function).
So the fact that two waves are in phase means that the maximums of their electric field coincide in time.
Answer:
Average speed = distance/time
From 1 to 9 seconds:
Distance covered = 1 - 0.2 = 0.8 km
Time = 9 - 1 = 8 sec
Average speed = 0.8 km / 8 sec
Average speed = 0.1 km/s .
The average speed for the whole test is 1.6 km / 20 sec = 0.08 km/sec. A graph of speed vs time would average out as a horizontal line at 0.08 km/sec from 1 sec to 21 sec. The area under it would be (0.08 km/s) x (20 sec) = 1.6 km.
Surprise surprise ! The area under a speed/time graph is the distance covered during that time !
In closing, I want to express my gratitude for the gracious bounty of 3 points with which I have been showered. Moreover, the green breadcrust and tepid cloudy water have also been refreshing.
Explanation:
Answer:
2270 full wavelengths.
Explanation:
The wavelength 
of the sound wave (assuming sound speed of 
) is
.
Now, assuming the distance to the last row is 1947m, the number 
of wavelengths that fit into this distance are
which is 2270 full wavelengths.
Hence, there are 2270 full wavelengths between the stage and the last row of the crowd.
Answer:
Well sports back then were diffrent for example football was soccer and soccer was not even a word!!! They had diffrent rules too. HOPE THIS HELPS GOOD LUCK!!!!!
Explanation:
After one day, the rate of increase in Delta Cephei's brightness is;0.46
We are informed that the function has been used to model the brightness of the star known as Delta Cephei at time t, where t is expressed in days;
B(t)=4.0+3.5 sin(2πt/5.4)
Simply said, in order to determine the rate of increase, we must determine the derivative of the function that provides
B'(t)=(2π/5.4)×0.35 cos(2πt/5.4)
Currently, at t = 1, we have;
B'(1)=(2π/5.4)×0.35 cos(2π*1/5.4)
Now that the angle in the bracket is expressed in radians, we can use a radians calculator to determine its cosine, giving us the following results:
B'(1)=(2π/5.4)×0.3961
B'(1)≈0.46
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