Consider a boat heading due east at 15 miles/hour. The water's current is moving at 7.1 miles/hour at 45º south of east. Drag ve
2 answers:
You might be interested in
Answer:43.33 cm mark
Explanation:
Given
mass 1 is located at the 10 cm mark with weight of 15 kg
mass 2 is located at 60 cm mark with weight of 30 kg
string should be attached between them to balance the system
so the distance between the the two masses is 50 cm
For system to be balance torque of both the weight must nullify each other
Let us suppose string is at a distance of x cm from 15 kg mass so 30 kg mass is at a distance of 50-x cm
Balancing torque
so string should be at a mark of 10+33.33=43.33 cm
We have that with v_1 =v this goes to show that the velocity of the bigger block after the collision takes place is v
From the question we are told
Suppose the blocks collide elastically. picking the positive direction to the right, what is the velocity of the bigger block after the collision takes place?
Generally the equation for Momentum is mathematically given as
P=mv
Therefore
Hence
Therefore
Hence
Now
with v_1 =v this goes to show that the velocity of the bigger block after the collision takes place is v
For more information on this visit
Answer:
from the center of the earth.
Explanation:
We have a system of Earth & Moon:
- we have the mass of earth,
- mass of the moon,
- distance between the center of the earth and the moon
Now we assume the origin of the system to be at the center of the earth.
Now for the center of mass of this system:
here:
are the distance of the centers (center of masses) of the Earth and the Moon from the origin of the system.
∵ since we have taken the point as the origin of the system.
now putting the values in the above equation:
from the center of the earth.