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igomit [66]
3 years ago
14

Consider a boat heading due east at 15 miles/hour. The water's current is moving at 7.1 miles/hour at 45º south of east. Drag ve

ctors for the boat and the current into the vector addition simulation.
What do Rx, Ry, , and |R| represent in terms of the force of the current, and what do they represent in terms of the forces moving the boat?
Physics
2 answers:
givi [52]3 years ago
7 0

If a boat is going East at 15mph and there is a water current going southeast at 45° then the boat is being drifted southward.  So since the current is going at an angle then it has a x and y component.  So Rx refers to the x-component force of the current and Ry refers to the y-component of the current, and |R| refers to the magnitude of these forces.

xxTIMURxx [149]3 years ago
4 0

Answer:

The boat velocity is 20.6 mph and  14 south of east

Explanation:

For this exercise it is best to write the speeds based on its components x and y

Boat    V1x = 15 mph

Water  V2 = 7.1 mph

           θ = - 45º

 Where the angle is measured from the x axis, the negative indicates that it is measured on an hourly basis

           V2x = V2 cos (-45) = 7.1 (0.707)

           V2y = V2 sin (-45) = 7.1 (-0.707)

           V2x = 5.0 mph

           V2y = -5.0 mph

The total system speed is the sum of each component

          Vx = V1x + V2x

          Vy = V1y + V2y

          Vx = 15 + 5.0

          Vy = 0 -5

          Vx = 20 mph

          Vy = -5.0 mph

We can give result in the form of magnitude and angle

          V² = Vx² + Vy²

          θ = tan-1 (Vy / Vx)

          V = √ [20² ++ (-5)²]

          θ = tan-1 (-5/20)

         

         V = 20.6 mph

         θ = -14º

 The boat velocity is 20.6 mph and  14 south of east

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This is the period in a simple harmonic motion which is 2 seconds in this question.

<h3>What is Period ?</h3>

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Keith_Richards [23]

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Tarzan and Jane. Because of your concern that incorrect science is being taught to children when they watch cartoons on TV, you
creativ13 [48]

Answer:

The maximum height Tarzan and Jane can swing as a fraction of her initial heigh is ⅓h

Explanation:

Let

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M = Mass of Jane

Given

M = 2m

To calculate the maximum height Tarzan and Jane can swing, we make use of the potential energy at their initial and final position.

Reason being that;

At both the initial and final position, velocity is 0, so there's no kinetic energy.

And the potential energy remains the same (i.e constant) at any given point in the system.

Using P.E = mgh.

At initial position, PE1 = mgh

At final position, PE2 = (m + M)gH.

Where h and H represent the initial and final heights.

m + M is the new weight after Jane and Tarzan swing

Equating PE1 to PE2

mgh = (m + M)gH

By substituton (M = 2m)

mgh = (m + 2m)gH

mgh = 3mgH

Make H the subject of the formula

H = mgh/3mg

H = ⅓h

Hence, the maximum height Tarzan and Jane can swing as a fraction of her initial heigh is ⅓h

From the question, the new height looks to be about ½ that of Jane's original position; i.e. ½h

The calculated height is smaller than what the cartoon is showing;

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3 years ago
On a horizontal surface is located
Ierofanga [76]

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The force of static friction exerts up to 80 N on the object, since that's the minimum required force needed to get it moving, which means the coefficient of <u>static</u> friction <em>µ</em> is such that

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Moving at constant speed, there is a kinetic friction force of 40 N opposing the object's motion, so that the coefficient of <u>kinetic</u> friction <em>ν</em> is

40 N = <em>ν</em> (196 N)   →   <em>ν</em> = (40 N)/(196 N) ≈ 0.204

And so the closest answer is C.

(Note: <em>µ</em> and <em>ν</em> are the Greek letters mu and nu)

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3 years ago
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