All categories

3 years ago

Determine the chemical formula for the compound, potassiumtrisethylenediamine chromate(III).

Chemistry

1 answer:

Korolek [52]3 years ago

8 0

Answer: The correct answer is (A).

Explanation:

Potassium-trisethylene-diamine chromate(III)

Potassium is coming first in name which means that potassium is present as cation.

In the complex, 3 molecules of 'ethylene-diamine' is present as an dianion and forms a complex with Chromium (III) metal, making the overall charge on the coordination sphere as (-3).

So, to make a neutral complex, 3 potassium ions are required.

Hence, the structure of the complex is $K_3[Cr(NH_2CH_2CH_2NH_2)_3]$

You might be interested in

When 0.200 grams of Al reacts with 15.00 mL of a 0.500 M copper(II) chloride solution, how many moles of solid Cu would be produ

Naddik [55]

When The balanced equation is:
2Al + 3CuCl2 ⇒3 Cu + 2AlCl3
So, we want to find the limiting reactant:
1- no. of moles of 2Al = MV/n = (Wt * V )/ (M.Wt*n*V) = Wt / (M.Wt *n)

where M= molarity, V= volume per liter and n = number of moles in the balanced equation.
by substitute:
∴ no. of moles of 2Al = 0.2 / (26.98 * 2)= 0.003706 moles.
2- no.of moles of 3CuCl2= M*v / n = (0.5*(15/1000)) / 3= 0.0025 moles.
So, CuCl2 is determining the no.of moles of the products.
∴The no. of moles of 3Cu = 0.0025 moles.
∴The no.of moles of Cu= 3*0.0025= 0.0075 moles.
and ∵ amount of weight (g)= no.of moles * M.Wt = 0.0075 * M.wt of Cu
= 0.0075 * 63.546 =0.477 g

3 0

2 years ago

The Arrhenius plot of the reaction has a downward slope of 1.5 x104. Calculate the time required to reduce the concentration of

madam [21]

1.5?10000 10% then add it up

4 0

2 years ago

Br2(g) cl2(g)⇌2brcl(g) δh∘f for brcl(g) is 14. 6 kj/mol. Δs∘f for brcl(g) is 240. 0 j/mol

max2010maxim [7]

The Change in Gibb's free energy, ΔG for the reaction at 298K is; -56.92KJ.

<h3>Gibb's free energy of reactions</h3>

It follows from the Gibb's free energy formula as expressed in terms of Enthalpy and Entropy that;

ΔG = ΔH - TΔS

On this note, it follows that;

ΔG = 14.6 - (298× 0.24)

Hence, the Gibb's free energy for the reaction is;

ΔG = 14.6 - 71.52
ΔG = -56.92KJ

Remarks: The question requires that we determine the Gibb's free energy for the reaction at 298K.

Read more on Gibb's free energy;

brainly.com/question/13765848

5 0

1 year ago

Read 2 more answers

What is the mass of 6.02 x 1023 particles of rubidium carbonate

Firdavs [7]

Answer:

Explanation:

84.97

4 0

2 years ago

Which structural adaptation would help a plant survive better in a shady environment?

Gekata [30.6K]

Answer:C.

large leaves

Explanation: I took the test

3 0

3 years ago