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Alinara [238K]
3 years ago
8

What major body of water did the new states of kentucky and tennessee

Physics
1 answer:
chubhunter [2.5K]3 years ago
6 0

The major water body given access to the new states of Kentucky and tennessee was the Mississippi river.

<u>Explanation:</u>

The Mississippi river serves to be the <em>second ranked</em> longest river located in the North America. the access was given to United States by the Kentucky state and Tennessee state.

The access granted was requested in order to serve the purpose of<em> trade</em> across. The Mississippi river have been often remarked as the super highway to the sea. <em>Irrigation of crops with the transportation aid along with the food availability</em>, all calls for the grant access to the major water body.

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When a certain rubber band is stretched a distance x, it exerts a restoring force of magnitude f = ax, where a is a constant. th
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Given:
F = ax
where
x = distance by which the rubber band is stretched
a =  constant

The work done in stretching the rubber band from x = 0 to x = L is
W=\int_{0}^{L} Fdx = \int_{0}^{L}ax \, dx = \frac{a}{2}  [x^{2} ]_{0}^{L} =  \frac{aL^{2}}{2}

Answer:  \frac{aL^{2}}{2}

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4 years ago
A rock is dropped from a vertical cliff. The rock takes 3.00 s to reach the ground below the cliff. A second rock is thrown vert
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Answer:

Velocity v= 12.25 \frac{m}{s}

Explanation:

The first rock dropped give the distance Y in meters

Y_{f}=Y_{o}+v_{o}*t +\frac{1}{2}*a*t^{2}\\   Y_{f}=\frac{1}{2}* 9.8 \frac{m}{s^{2} }* 3^{2}   \\Y_{f}=44.1 m

Now the motion of the second rock the time change so to know the velocity

Y_{f}= Y_{o} +v_{o}*t +\frac{1}{2}*a *t^{2} \\v_{o}*t= -Y_{f} +\frac{1}{2} *a*t^{2} \\v_{o} =\frac{-44.1 +0.5 * 9.8* s^{2} }{2} \\v_{o}=  12.25 \frac{m}{s}

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3 years ago
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Answer:

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Explanation:

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Suppose that there are N=108 two-state systems, each with energy difference E=6 × 10-21 J between the two states. The environmen
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Answer:

The value of \dfrac{dU}{dM} is 6\times10^{-29}\ J/unit.

Explanation:

Given that,

Number N=10^{8}

Energy difference = 6\times10^{-21}\ J[/tex]

Temperature T =300 K

We need to calculate the value of \dfrac{dU}{dM}

We know that,

\dfrac{dU}{dM}=\dfrac{energy\ difference}{Change\ in\ number\ of\ system}

\dfrac{dU}{dM}=\dfrac{6\times10^{-21}}{10^{8}}

\dfrac{dU}{dM}=6\times10^{-29}\ J/unit

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Please answer quickly
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