Any key words? That they put there
Answer:
Total work done to lift barbell = 890 J
Explanation:
Given:
Weight of barbell (F) = 445 N
Height (Distance) = 2 meter
Find:
Total work done to lift barbell = ?
Computation:
⇒ Work = Force(F) × Distance
⇒ Total work done to lift barbell = Weight of barbell × Distance
⇒ Total work done to lift barbell = 445 N × 2 meter
⇒ Total work done to lift barbell = 890 J
Answer:
initial velocity (u) = 200m/s
final velocity (v) = 350 m/s
time (t) = 15s
acceleration (a) = ?
NOW,
a=v-u/t
a= 350-200/15
a= 50/15
a= 3.3333
Explanation:
it's too easy just u need to understand the question . and go according to it's content .
main thing to memorize is it's simple formula.
I HAVE SOLVE THIS QNA. IN VERY
SIMPLE AND UNDERSTANDABLE FORM.
I høpë u hađ uņdērstøöď ťhìs şølutîóñ
:verý ×wəłł.
When you're dealing with quantities that produce very large or very small numbers in the units that you're using; like meters to Neptune, or kilograms in one Hydrogen atom.