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Mariulka [41]
3 years ago
8

Two glass marbles (1 and 2), each supported by a nylon thread, are rubbed against a piece of silk and then are placed near a thi

rd glass marble (3), also supported by a similar thread. Assuming that marble 3 has not been in contact with the piece of fabric, which of the following statements best describes the situation when the three marbles are brought together?a.) Marbles 1 and 2 attract each other, but no interaction occurs with marble 3.b.) Both marbles 1 and 2 attract marble 3.c.) The three marbles will repel each other.d.) Marbles 1 and 2 repel each other, but no interaction occurs with marble 3.
Physics
1 answer:
almond37 [142]3 years ago
7 0

Answer:

d.) Marbles 1 and 2 repel each other, but no interaction occurs with marble 3.

Explanation:

By rubbing 1 and 2 with silk, the two marbles get positively charged however marble 3 is neutral because it did not have any interaction with any charge. So the correct answer is d.

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A boy held a ball in the air what force is he applying?
Delvig [45]

Answer:

strength

Explanation:

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3 years ago
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An object, initially at rest moves 250m in 17s. What is it's acceleration?
Gekata [30.6K]
With the values you've given, only velocity can be found.
Acceleration is rate of change of velocity

d= 250s
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a= d/t
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3 years ago
Water enters a cylindrical tank through two pipes at rates of 250 and 100 gal/min. If the level of the water in the tank remains
tester [92]

Answer:

The total amount of water that enters the tank is:

250 gal/min + 100 gal/min = 350gal/min.

Then, if the level of the water remains constant, this means that the water leaves the tank at a rate of 350gal/min.

We know that the diameter of the pipe is 8 inches, then the area of the pipe is:

A = pi*(d/2)^2 = 3.14*(4in)^2 = 50.24in^2

now, the flow can be calculated as:

Q = v*A = (velocity*area)

if we want to write our velocity in inches per minute, then we need to write the entering flow in cubic inches:

1 gallon = 231 in^3

then:

350gal/min = (350*231) in^3/min = 80,850 in^3/min.

Then the water that leaves the tank must be the same amoun, we have:

Q = 80,850 in^3/min. = v*A = v*50.24in^2

v =  (80,850in^3/min)/50.24in^2 = 1609.3 in/min.

The velocity of the flow leaving the tank is 1609.3 in/min.

3 0
4 years ago
Mark creates a graphic organizer to review his notes about electrical force. Which labels belong in the regions marked X and Y?
sveta [45]

Answer:

The correct answer is A

Explanation:

The question requires as well the attached image, so please see that below.

Coulomb's Law.

The electrical force can be understood by remembering Coulomb's Law, that  describes the electrostatic force between two charged particles. If the particles have charges q_1 and q_2, are separated by a distance r and are at rest relative to each other, then its electrostatic force magnitude on particle 1 due particle 2 is given by:

|F|=k \cfrac{q_1 q_2}{r^2}

Thus if we decrease the distance by half we have

r_1 =\cfrac r2

So we get

|F|=k \cfrac{q_1 q_2}{r_1^2}

Replacing we get

|F|=k \cfrac{q_1 q_2}{(r/2)^2}\\|F|=k \cfrac{q_1 q_2}{r^2/4}

We can then multiply both numerator and denominator by 4 to get

|F|=k \cfrac{4q_1 q_2}{r^2}

So we have

|F|=4 \left(k \cfrac{q_1 q_2}{r^2}\right)

Thus if we decrease the distance by half we get four times the force.

Then we can replace the second condition

q_{2new} =2q_2

So we get

|F|=k \cfrac{q_1 q_{2new}}{r_1^2}

which give us

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Thus doubling one of the charges doubles the force.

So the answer is A.

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