Ask question

Ask question

All categories

jarptica [38.1K]

3 years ago

10

Inferences are A. never made by scientists. B. questions that are made by studying conclusions or predictions. C. exactly the sa

me as observations. D. conclusions or predictions that are made by studying observations.

1 answer:

e-lub [12.9K]3 years ago

4 0

The answer would be, D. because ive taken the test.

You might be interested in

A gas at 45 o C occupies 5.22 L. At what temperature will the volume be 6.87 L?

vfiekz [6]

Hhbbb. Bbhbbbbhhbbjjnjnmmmkkkkjn

5 0

2 years ago

The solubility of acetanilide is 12.8 g in 100 mL of ethanol at 0 ∘C, and 46.4 g in 100 mL of ethanol at 60 ∘C. What is the maxi

weqwewe [10]

Answer: 72.41% and 26.90% respectively.

Explanation:

At 60°C, you can dissolve 46.4g of acetanilide in 100mL of ethanol. If you lower the temperature, at 0°C, you can dissolve just 12.8g, which means (46.4g-12.8g)=33.6g of acetanilide must have precipitated from the solution.

We can calculate recovery as:

$\%R=\frac{crystalized\ mass}{initial\ mass}*100 =\frac{33.6\ g}{46.4\ g}*100=72.41\%$

So the answer to the first question is 72.41%.

For the second part just use the same formula, the mass of the precipitate is the final mass minus the initial mass, (171mg-125mg)=46mg.

$\%R=\frac{crystalized\ mass}{initial\ mass}*100 =\frac{46\ mg}{171\ mg}*100=26.90\%$

So the answer to the second question is 26.90%.

3 0

2 years ago

What is the mass of the oxygen in one mole of calcium phosphate

nevsk [136]

Answer:

16.00 g/mol

Explanation:

7 0

2 years ago

Read 2 more answers

When the water inside a living cell freezes, the ice crystals damage the cell. The wood frog is a unique creature that can survi

professor190 [17]

But i think its B but i need answer too

4 0

2 years ago

Due to the small and highly electronegative nature of fluorine, the oxyacids of the this element are much less common and less s

steposvetlana [31]

We are told we have an oxyacid of the formula HOFO. We will assume the atoms are in this order and will draw a proper lewis structure for this compound by first drawing bonds between each of the 4 atoms and then place the remaining electron pairs on each atom:
.. .. ..
H - O - F - O:
·· ·· ··
We can calculate the formal charge of an atom using the following formula:

Formal charge = [# of valence electrons] - [# of non-bonded electrons + # of bonds]

H: Formal charge = [1]-[0+1] = 0

O: Formal charge = [6]-[4+2] = 0

F: Formal charge = [7]-[4+2] = +1

O: Formal charge = [6]-[6+1] = -1

As we can see the overall charge of the molecule is neutral since the fluorine as a +1 charge and the oxygen a -1 charge.

4 0

2 years ago