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aleksandrvk [35]
3 years ago
11

Ed rolls a ball forward across the floor. It hits a wall 12 meters away and rolls back along the same path. It stops 5 meters fr

om the wall. What is the displacement of the ball? 17 meters forward 5 meters forward 7 meters forward 12 meters forward
Physics
2 answers:
slamgirl [31]3 years ago
8 0
I believe it's 7 meters positive (foward)
dedylja [7]3 years ago
8 0
The displacement is 7 meters forward. 

it rolled forward 12 and then 5 back.

12 forward - 5 backward = <span>7

</span><span>hope this helps :)</span>
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A triangle has two sides of length 10 cm and 14 cm. what can you say about the length of the third side?
Anton [14]

A side of any triangle is less than the sum of the other two sides so the third side must be less than 24cm.

<h3>What is a triangle?</h3>

A triangle is a 3-sided shape that is occasionally referred to as a triangle. There are three sides and three angles in every triangle, some of which may be the same.

The sum of all three angles inside a triangle will be 180° and the area of a triangle is given as (1/2) × base × height.

There are many types of triangles such that right-angle triangles, equilateral triangles, and much more.

In any triangle, the sum of two sides is always greater than the third side.

If the third side is equal to the sum of two sides then it will be a straight line rather than a triangle.

It means 10 + 14 > third side

24 cm > third side

Hence "A side of any triangle is less than the sum of the other two sides so the third side must be less than 24cm".

For more about triangles,

brainly.com/question/2773823

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What is the wavelength, in nm, of a photon with energy
lara31 [8.8K]

Answer:

(a)  λ = 4136 nm → infrared

(b) λ = 413.6 nm → visible light

(c) λ = 41.36 nm → ultraviolet

Explanation:

The wavelength of infrared is on the range of 700 nm to 1000000 nm

The wavelength of visible light is between 400 nm and 700 nm

The wavelength of ultraviolet ray on the range of 10 nm to 400 nm

The wavelength of photon is given by;

E = hf

f is the frequency of the wave = c / λ

E = h\frac{c}{\lambda}\\\\ \lambda = \frac{hc}{E}

Where;

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h is Planck's constant = 6.626 x 10⁻³⁴ J/s

(a) 0.3 eV = 0.3 x 1.602 x 10⁻¹⁹ J

\lambda = \frac{(6.626 * 10^{-34})(3*10^8)}{(0.3)*(1.602*10^{-19})}\\\\\lambda = 4.136 *10^{-6} \ m

λ = 4136 x 10⁻⁹ m

λ = 4136 nm → infrared

(b) 3.0 eV

\lambda = \frac{(6.626 * 10^{-34})(3*10^8)}{(3)*(1.602*10^{-19})}\\\\\lambda = 4.136 *10^{-7} \ m

λ = 413.6 x 10⁻⁹ m

λ = 413.6 nm →visible light

(c) 30 eV

\lambda = \frac{(6.626 * 10^{-34})(3*10^8)}{(30)*(1.602*10^{-19})}\\\\\lambda = 4.136 *10^{-8} \ m

λ = 41.36 x 10⁻⁹ m

λ = 41.36 nm →ultraviolet

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Rudiy27
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22:54 is the answer you are looking for
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