Answer:
Electric field E = kQ/r^2
Distance between charges = 6.30 - (-4.40) = 10.70m
Say the neutral point, P, is a distance d from q1. This means it is a distance (10.70 - d) from q2.
Field from q1 at P = k(-9.50x^10^-6) / d^2
Field from q2 at P = k(-8.40x^10^-6) / (10.70-d)^2
These fields are in opposite directions and are equal magnitudes if the resultant field = 0
k(-9.50x^10^-6) / d^2 = k(-8.40x^10^-6) / (10.70-d)^2
9.50 / d^2 =8.40 / (10.70-d)^2
d^2 / (10.70-d)^2 = 9.50/8.40 = 1.131
d/(10.70-d) = sqrt(1.1331) = 1.063
d = 1.063 ((10.70-d)
= 10.63 - 1.063d
2.063d = 10.63
d = 5.15m
The y coordinate where field is zero is 6.30 - 5.15 = 1.15m
Explanation:
E) Protons, neutrons, and electrons
C.<span>Molecules can move more rapidly and freely and change states.
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"700 watts" means 700 joules of work per second.
"300 watts" means 300 joules of work per second.
If the labels on both machines are true, and both machines
are loaded to their full capacity, then the 700-watt engine
is doing work faster than the 300-watt one.
Answer:
The racetrack is 996.7 meters long
Explanation:
Convert 251km/h to km/s (kilometers per second)
3600 seconds in an hour, so:
251/3600 = 0.0697km/s
Convert km/s to m/s (meters per second)
1000 meters in a kilometer, so:
0.0697*1000 = 69.7m/s
Find length of racetrack:
69.7m/s*14.3s = 996.7m
If the racer travels 69.7 meters in one second and it takes 14.3 seconds to complete a lap, the racetrack is 996.7 meters long.
