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sesenic [268]
3 years ago
8

Olympic skier Tina Maze skis down a steep slope that descends at an angle of 30∘ below the horizontal. The coefficient of slidin

g friction between her skis and the snow is 0.10.
I found Maze's acceleration which is 4.1 m/s^2. But how do you determine Maze's speed 4.0 s after starting?
Physics
1 answer:
LekaFEV [45]3 years ago
5 0

net force on Maze during his sliding downwards motion

F = mgsin30 - \mu mg cos30

now we will have

F = mg(sin30 - 0.10cos30)

now to find the acceleration we will have

a = \frac{F}{m}

a = g(sin30 - 0.10cos30)

a = 9.81(0.5 - 0.10(0.866))

a = 4.1 m/s^2

now to find the speed after 4 s is given by kinematics

v_f - v_i = at

here we know that

v_i = 0

v_f - 0 = 4.1(4)

v_f = 16.22 m/s

so Maze speed after 4 s will be 16.22 m/s

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2 kg steel ball is dropped straight down ont a hard horixontal florr and bounces straight up . the balls speed just before and j
Rainbow [258]

Answer:

40 \frac{kg*m}{s}

Explanation:

Impulse-momentum theorem states that impulse is equal to the change of momentum:

\overrightarrow{J}=\overrightarrow{p}_{f}-\overrightarrow{p}_{i} (1)

with pf the final momentum and pi the initial momentum. Knowing that momentum is mass (m) times velocity (1) is:

\overrightarrow{J}=m \overrightarrow{v}_{f}- m \overrightarrow{v}_{i}

It's important to note that we're dealing with vector quantities so direction matters. If we choose towards the floor positive direction then the initial velocity is positive and the final velocity is negative, so:

\overrightarrow{J}=-(2kg)(10\frac{m}{s}) - (2.0kg)(10\frac{m}{s})

\overrightarrow{J}=-40 \frac{kg*m}{s}

So, the impulse delivered to the floor is 40 \frac{kg*m}{s}

5 0
3 years ago
Force of 99N and 64N act on an object of mass27 kg. what is the acceleration of the object
zimovet [89]
That all depends on the angle between the two forces.

It could be anything between 1.3 m/s² in the direction of the larger force, if
they're in opposite directions, all the way around to 6.04 m/s² in the direction
of both of them if they're both in the same direction.

That includes magnitudes between 1.3n and 6.04n directed somewhere between
the two forces if they're in different, unrelated directions.


8 0
3 years ago
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The heat transfer depicted in the image is MOST likely
stealth61 [152]

Answer:

Convection

Explanation:

 

8 0
3 years ago
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A plate of glass with parallel faces having a refractive index of 1.52 is resting on the surface of water in a tank. A ray of li
inna [77]

Answer:

26.22degrees.

Explanation:

Go through the attachment for a step by step simplified method of how the answer is gotten.

3 0
3 years ago
What force must be applied to push a carton weighing 245 N up a 15.0° incline, if the coefficient of kinetic friction is 0.340?
Sliva [168]

Answer:

<h3>143.815 N</h3>

Explanation:

when a person is pushing a carton in an inclined plane there is two forces acting against  the applied force,

  • component of gravity or mgsinθ
  • friction or μmgcosθ

the carton goes up ( constant velocity ) only if sum of these two forces becomes equal to applied force

from the question,

weight of the carton,mg = 245 N

angle of incline,θ = 15°

coefficient of friction, μ = 0.340

∵ the applied force, F = mgsinθ + μmgcosθ

                                    = mg ( sinθ + μcosθ)

                                    = 245 ( sin 15° + 0.340 cos 15°)

                                    = 245 ( 0.259 + 0. 328)

                                    = 143.815 N

7 0
3 years ago
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