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sesenic [268]
3 years ago
8

Olympic skier Tina Maze skis down a steep slope that descends at an angle of 30∘ below the horizontal. The coefficient of slidin

g friction between her skis and the snow is 0.10.
I found Maze's acceleration which is 4.1 m/s^2. But how do you determine Maze's speed 4.0 s after starting?
Physics
1 answer:
LekaFEV [45]3 years ago
5 0

net force on Maze during his sliding downwards motion

F = mgsin30 - \mu mg cos30

now we will have

F = mg(sin30 - 0.10cos30)

now to find the acceleration we will have

a = \frac{F}{m}

a = g(sin30 - 0.10cos30)

a = 9.81(0.5 - 0.10(0.866))

a = 4.1 m/s^2

now to find the speed after 4 s is given by kinematics

v_f - v_i = at

here we know that

v_i = 0

v_f - 0 = 4.1(4)

v_f = 16.22 m/s

so Maze speed after 4 s will be 16.22 m/s

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The density of a glass is 2.5 g/cm3. if the glass breaks, what is the density of the smaller pieces​
sp2606 [1]

Answer:

See the explanation below.

Explanation:

Density will remain the same since density is the relationship between mass and volume. As we can see in the equation below.

Ro=m/V

where:

Ro = density = 2.5 [g/cm³]

m = mass [g]

V = volume [cm³]

In such a way that when the glass is broken the small fragments retain the same density ratio. That is, each fragment has a small mass and a small volume. That's why the density remains the same.

4 0
3 years ago
A ball rolls horizontally with a speed of 9.6 mis off of the edge of a tal platform. If the ball lands 5.7 m from the point on t
horrorfan [7]

Answer:

1) The height of the platform is 1.7 m

2) The ball is 0.59 s in the air.

Explanation:

The position of the ball at time "t" is given by the following position vector:

r = (x0 + v0x · t, y0 + v0y · t + 1/2 · g · t²)

Where:

r = vector position at time t

x0 = initial horizontal position

v0x = initial horizontal velocity

t = time

y0 = initial vertical position

v0y = initial vertical velocity

g = acceleration due to gravity (-9.8 m/s² if the upward direction is considered positive)

Please, see the figure for a better understanding of the problem. Notice that the frame of reference is located at the edge of the platform. In this case, x0 = 0 and y0 = 0. Initially, the ball does not have a vertical velocity so that v0y = 0. The position vector will be as follows:

r = (v0x · t, 1/2 · g · t²)

Seeing the figure, notice that when the ball reaches the ground the x-component of its position vector will be 5.7 m. Then:

x = v0x · t

5.7 m = 9.6 m/s · t

<u>t = 0.59 s</u>

The ball reaches the ground in 0.59 s. At this time, the magnitude of the y-component of the position vector will be the height of the platform (see figure). Then:

y = 1/2 · g · t²

y = -1/2 · 9.8 m/s² · (0.59)²

y = -1.7 m

The height of the platform is 1.7 m.

6 0
3 years ago
The mass of the bicycle and rider is 60 kg and the total area of the tyres in contact with
AleksAgata [21]

Answer:

a little

Explanation:

First of all, it's not how you spell "tyres", it is tires.

Second of all, you already know the Mass so what you need to find out now is  contact the road. You Know that your number and letter are squared so that would turn into 6m x 2.4. Then you do the math do continue on to finish it. Have a great day!! Good luck with the answer!!

3 0
3 years ago
Two high-current transmission lines carry currents of 29.0 A and 78.0 A in the same direction and are suspended parallel to each
jarptica [38.1K]

Answer with Explanation:

We are given that

I_1=29 A

I_2=78 A

d=38 cm=\frac{38}{100}=0.38 m

1 m=100 cm

a.Length of segment,l=20 m

Magnetic force ,F=\frac{2\mu_0I_1I_2 l}{4\pi d}

\frac{\mu_0}{4\pi}=10^{-7}

Substitute the values

F=\frac{10^{-7}\times 29\times 78\times 20}{0.38}=0.0119 N

Hence, the magnetic force exert by each segment on the other=0.0119 N

b.We know that when current carrying in the wires are in same direction then the force will attract to each other.

Hence, the force will be attractive.

4 0
3 years ago
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Answer:

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