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sesenic [268]
3 years ago
8

Olympic skier Tina Maze skis down a steep slope that descends at an angle of 30∘ below the horizontal. The coefficient of slidin

g friction between her skis and the snow is 0.10.
I found Maze's acceleration which is 4.1 m/s^2. But how do you determine Maze's speed 4.0 s after starting?
Physics
1 answer:
LekaFEV [45]3 years ago
5 0

net force on Maze during his sliding downwards motion

F = mgsin30 - \mu mg cos30

now we will have

F = mg(sin30 - 0.10cos30)

now to find the acceleration we will have

a = \frac{F}{m}

a = g(sin30 - 0.10cos30)

a = 9.81(0.5 - 0.10(0.866))

a = 4.1 m/s^2

now to find the speed after 4 s is given by kinematics

v_f - v_i = at

here we know that

v_i = 0

v_f - 0 = 4.1(4)

v_f = 16.22 m/s

so Maze speed after 4 s will be 16.22 m/s

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c) What is moment of inertia? How is it defined (write an equation, explaining all the terms)? What is the parallel axis princip
ipn [44]

Answer:

Check Explanation

Explanation:

What is moment of inertia?

Mathematically Moment of Inertia I = Mr²

where m = mass of the body

r = distance of body to the rotattinal axis

This is a  quantity expressing a body's tendency to resist angular acceleration, which is the sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation.

What is the parallel axis principle for moment of inertia?

The theorem of parallel axis states that the moment of inertia of a body about an axis parallel to an axis passing through the centre of mass is equal to the sum of the moment of inertia of body about an axis passing through centre of mass and product of mass and square of the distance between the two axes.

(if the moment of inertia for a body is I for rotation about an axis that passes through its center of mass, what will be the moment of inertia, Ip, for rotation parallel to that axis?

Ip = I + Mα²

Explain the terms you use in the equation

where, α is the distance between two axes (also called the radius of gyration)

I is more moment of inertia about the centre of mass

Ip is the momont of inertia of the rotation parallel to the axis that passes through the centre of mass

M is the mass of the body

4 0
3 years ago
5. Graph A below plots a race car's speed for 5 seconds. The car's rate of acceleration is 6 m/s^2
Georgia [21]

Answer:

The answer is below

Explanation:

We are to check if the statement is true of false. If it is false, we correct the statement.

Solution:

Acceleration is the time rate of change of velocity. It is the ratio of the change in velocity to the change in time. The acceleration can be gotten from a velocity time graph by finding the slope of the graph.

The x coordinate represent the time and the y coordinate velocity.

5) Graph A passes through the point (0, 0) and (4, 24). Therefore the acceleration (slope) is:

Acceleration = \frac{24-0}{4-0}=6\ m/s^2

This is correct.

6) Graph B is a straight line of 12 m/s. It passes through (0, 12) and (4, 12). Hence:

Acceleration = \frac{12-12}{4-0}=0\ m/s^2

This is false.

Therefore the acceleration of graph B is 0 m/s².

8 0
2 years ago
An astronaut exploring a distant solar system lands on an unnamed planet with a radius of 2530 km. When the astronaut jumps upwa
Natali [406]

Answer:

1.38*10^18 kg

Explanation:

According to the Newton's law of universal gravitation:

F=G*\frac{m_a*m_p}{r^2}

where:

G= Gravitational constant (6.674×10−11 N · (m/kg)2)

ma= mass of the astronaut

mp= mass of the planet

F=m_a.a\\(v_f )^2=(v_o)^2+2.a.\Delta y\\\\a=\frac{(v_f)^2-(v_o)^2}{2.\Delta y}\\\\a=\frac{(0)^2-(4.29m/s)^2}{2.0.64m}=14.38m/s^2\\\\F=m_a*14.38m/s^2

so:

m_a*14.38m/s^2=(6.674*10^{-11}N.(m/kg)^2)*\frac{m_a.m_p}{(2.530*10^3m)^2}\\m_p=\frac{14.38m/s^2(2.530*10^3m)^2}{(6.674*10^{-11}N.(m/kg)^2)}\\\\m_p=1.38*10^{18}kg

7 0
3 years ago
In the Bohr model of the atom, an electron in an orbit has a fixed ____.
worty [1.4K]
The answer is C. an electron in an orbit has a fixed energy.
3 0
3 years ago
1. Most waves are caused by vibrations. What motion in a transmitting antenna causes the vibrations that produce radio waves?
morpeh [17]
The answer 1 is
The best-known use of radio waves is for communication; television, cellphones and radios all receive radio waves and convert them to mechanical vibrations in the speaker to create sound waves that can be heard.Electromagnetic radiation is transmitted inwaves or particles at different wavelengths and frequencies.

the answer 2 is

Radio Waves: Instant Communication
Microwaves: Data and Heat

i think the answer number 3 is
It is all about wavelength versus tunnel diameter. The wavelength of GPS is about 20cm it would happily propagate in any normal tunnel if it could get in but the earth and other structures absorb it. AM radio (600kHz - 1500kHz) cannot propagate in any normal tunnel because the wavelength is too long (500m-200m) relative to the diameter, and thus gets reflected at the entrance. FM (100MHz ~ 3m) would propagate and it does for a while but then it suffers reflections
8 0
2 years ago
Read 2 more answers
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