Answer:
The velocity of the players will be <u>2.88 m/s</u> in the <u>east</u> direction.
Explanation:
Let 'v' be the velocity of the players after collision.
Consider the east direction as positive direction.
Given:
Mass of the first player is, 
kg
Initial velocity of the first player is, 
m/s
Mass of the second player is, 
kg
Initial velocity of the second player is, 
m/s
In order to solve this problem we use the law of conservation of momentum which says that the total momentum must be conserved before and after the collision. So we can write:
Solving for v, we get:
Therefore, their velocity after the collision is 2.88 m/s.
The sign of the velocity after collision is positive. So, the players will move in the east direction only after collision.
Answer:
1.8 m/s
Explanation:
Draw a free body diagram of the block. There are four forces:
Normal force Fn up.
Weight force mg down.
Applied force F to the east.
Friction force Fn μ to the west.
Sum the forces in the y direction:
∑F = ma
Fn − mg = 0
Fn = mg
Sum the forces in the x direction:
F − Fn μ = ma
F − mg μ = ma
a = (F − mg μ) / m
a = (12 N − 6 kg × 9.8 m/s² × 0.15) / 6 kg
a = 0.53 m/s²
Given:
Δx = 3 m
v₀ = 0 m/s
a = 0.53 m/s²
Find: v
v² = v₀² + 2aΔx
v² = (0 m/s)² + 2 (0.53 m/s²) (3 m)
v = 1.8 m/s
Their average velocity is 0.98 m/s east.
Explanation:
The average velocity of an object is defined as the ratio between the displacement and the time taken:
The displacement is a vector connecting the initial point to the final point of motion: so, being displacement a vector, velocity is a vector as well, having the same direction of displacement.
Here, Heather and Matt walk 2.0 km eastward, so their displacement is
d = 2.0 km = 2000 m (east)
While the time they took is
Therefore, their average velocity is
And the direction is the same as the displacement (east).
Learn more about average velocity:
brainly.com/question/5248528
#LearnwithBrainly
Answer:
25100A
Explanation:
t= 1ms = 0.001s
q = 25.1C
From the relationship between charge and current , the charge is equal to the product of current and time
q = i×t
Where q = charge
i = current
t = time
i = q/t = 25.1/0.001
i = 25100A.
Answer:
oh for real?
Explanation:
The solubility of glucose at 30°C is
125 g/100 g water. Classify a solution made by adding 550 g of glucose to 400 mL of water at 30°C. Explain your classification, and describe how you could increase the amount of glucose in the solution without adding more glucose.
