Okay so this is in order of the blanks
matter
potential
kinetic
physical
food.
(2) gains 12 moles of electrons, easy, because it must retain the same mass in a balanced equation, so if there is no exterior mention of any electrons, such as the notation +12e-, than we must assume that the Oxygen took it at any rate.
<span>Due to limitations on typography, I will have to describe the equation instead of actually writing it.
Crude appearance.
18 18 0
F --> O + e
9 8 1
Detailed description. Each of the 3 components have both a left superscript and a left subscript which is a superscript and a subscript to the LEFT of the main figure unlike the usual right side that you see subscripts and superscripts.
The equation will be F with an 18 left superscript and a 9 left subscript to represent Florine with atomic weight of 18 and 9 protons.
Followed by a right arrow to indicate the direction the reaction is going.
Followed by the letter O with a left superscript of 18 and a left subscript of 8 to represent Oxygen with atomic weight of 18 and 8 protons.
Followed by a plus sign to indicate more.
Followed by either the lower case letter "e" or the upper case Greek character beta with a left superscript of 0 and a left subscript of 1 or +1 to represent the positron being emitted with a positive charge and an atomic weight of 0.</span>
Identify each element found in the equation. The number of atoms of each type of atom must be the same on each side of the equation once it has been balanced.
What is the net charge on each side of the equation? The net charge must be the same on each side of the equation once it has been balanced.
If possible, start with an element found in one compound on each side of the equation. Change the coefficients (the numbers in front of the compound or molecule) so that the number of atoms of the element is the same on each side of the equation. Remember, to balance an equation, you change the coefficients, not the subscripts in the formulas.
Once you have balanced one element, do the same thing with another element. Proceed until all elements have been balanced. It's easiest to leave elements found in pure form for last.
Check your work to make certain the charge on both sides of the equation is also balanced.
NH₄NO₃ - ammonium-nitrate.
(NH₄)₂CO₃ - ammonium carbonate.
NH₄CN - ammonium cyanide.
(NH₄)₃PO₄- ammonium phosphate.
Sn(NO₃)₄ - tin(IV) nitrate.
Sn(CO₃)₂ - tin(IV) carbonate.
Sn(CN)₄ - tin(IV) cyanide.
Sn₃(PO₄)₄ - tin(IV) phosphate.
Fe(NO₃)₃ - iron(III) nitrate.
Fe₂(CO₃)₃ - iron(III) carbonate.
Fe(CN)₃ - iron(III) cyanide.
FePO₄ - iron(III) phosphate.
Mg(NO₃)₂ - magnesium nitrate.
MgCO₃ - magnesium carbonate.
Mg(CN)₂ - magnesium cyanide.
Mg₃(PO₄)₂ - magnesium phosphate.
