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faust18 [17]
3 years ago
11

What is homologous series

Chemistry
2 answers:
BartSMP [9]3 years ago
5 0
It is a series of compound a same general formula
Leni [432]3 years ago
5 0
<span>It is a group of organic compounds,that have a similar structure and whose structures differ only by the number of CH2 units in the main carbon chain. It also have similar properties.</span>
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Describe the importance of plaster of paris
mojhsa [17]

Answer:

plaster is important because of the many uses you can make out of plaster

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Plz help!!!!!!
Sever21 [200]

this shows that magnesium is higher in the reactivity series than lead.

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5 0
4 years ago
Can someone please help me fill this out?​
Mamont248 [21]
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6 0
3 years ago
Please help! Thanks
trapecia [35]

Th actual yield of the reaction is 24.86 g

We'll begin by calculating the theoretical yield of the reaction.

2Na + Cl₂ → 2NaCl

Molar mass of Na = 23 g/mol

Mass of Na from the balanced equation = 2 × 23 = 46 g

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl from the balanced = 2 × 58.5 = 117 g

From the balanced equation above,

46 g of Na reacted to produce 117 g of NaCl.

Therefore,

11.5 g of Na will react to produce = (11.5 × 117) / 46 = 29.25 g of NaCl.

Thus, the theoretical yield of NaCl is 29.25 g.

Finally, we shall determine the actual yield of NaCl.

  • Percentage yield = 85%
  • Theoretical yield = 29.25 g
  • Actual yield =?

Actual yield = Percent yield × Theoretical yield

Actual yield = 85% × 29.25

Actual yield = 0.85 × 29.25 g

Actual yield = 24.86 g

Learn more about stoichiometry: brainly.com/question/25899385

7 0
3 years ago
A weather balloon is inflated to a volume of 27.9L at a pressure of 732mmHg and a temperature of 30.1?C. The balloon rises in th
masya89 [10]

Answer:

45.4 L

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Given ,  

V₁ = 27.9 L

V₂ = ?

P₁ = 732 mmHg

P₂ = 385 mmHg

T₁ = 30.1 ºC

T₂ = -13.6  ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (30.1 + 273.15) K = 303.25 K  

T₂ = (-13.6 + 273.15) K = 259.55 K  

Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac{{732}\times {27.9}}{303.25}=\frac{{385}\times {V_2}}{259.55}

\frac{385V_2}{259.55}=\frac{20422.8}{303.25}

148225V_2=6729708.26018

Solving for V₂ , we get:

<u>V₂ = 45.4 L</u>

7 0
4 years ago
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