1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Georgia [21]
3 years ago
15

Alkali metals are found in many common substances but are rarely found in pure form. Explain why this is in the case

Chemistry
1 answer:
Evgesh-ka [11]3 years ago
6 0

Alkali metals are rarely found in pure form because they are so reactive.

Alkali metals are in Group 1 of the Periodic Table.

They need to lose only one valence electron to reach a filled valence shell

Thus, they readily react wirh water and other chemicals in the earth to form compounds.

You might be interested in
Name the property of salt investigated in the above experiment
Snezhnost [94]

which experiment please involve a clip

7 0
2 years ago
What is the difference between an atom of silver and an<br> atom of gold?
a_sh-v [17]
Mass difference and difference in sub atomic particles
8 0
3 years ago
Read 2 more answers
Can someone do my homework pls!
Elza [17]

Answer:

Hi, a cheerful teen willing to help,

wishing you a splendiferous day ahead...

Explanation:

1ai. The most dense is Tungsten.

1aii. The least dense is Sodium.

1aiii. The strongest is Tungsten.

1b. All metals conduct electricity.

They are all magnetic except magnetic.

and all solid at room temperature except mercury.

1c. Mercury is a liquid at room temperature.

1d. Tungsten is used as filament for light bulbs due to its high melting point and it doesn't oxidize, this the filament won't melt.

1e. The lump of gold will sink because it is more dense than mercury.

7 0
3 years ago
Read 2 more answers
How much heat energy is required to convert 48.3 g of solid ethanol at -114.5 degree C to gasesous ethanol at 135.3 degree C? Th
OLEGan [10]

Answer:

7.21 × 10⁴ J

Explanation:

Ethanol is solid below -114.5°c, liquid between -114.5°C and 78.4°C, and gaseous above 78.4°C.

<em>How much heat energy is required to convert 48.3 g of solid ethanol at -114.5°C to gaseous ethanol at 135.3 °C?</em>

<em />

We need to calculate the heat required in different stages and then add them.

The moles of ethanol are:

48.3g.\frac{1mol}{46.07g} =1.05mol

Solid-liquid transition

Q₁ = ΔHfus . n = (4.60 kJ/mol) . 1.05 mol = 4.83 kJ = 4.83 × 10³ J

where,

ΔHfus: molar heat of fusion

n: moles

Liquid: from -114.5°C to 78.4°C

Q₂ = c(l) . m . ΔT = (2.45 J/g.°C) . 48.3g . [78.4°C-(-114.5°C)] = 2.28 × 10⁴ J

where,

c(l): specific heat capacity of the liquid

ΔT: change in the temperature

Liquid-gas transition

Q₃ = ΔHvap . n = (38.56 kJ/mol) . 1.05 mol = 40.5 kJ = 40.5 × 10³ J

where,

ΔHvap: molar heat of vaporization

Gas: from 78.4°C to 135.3°C

Q₄ = c(g) . m . ΔT = (1.43 J/g.°C) . 48.3g . (135.3°C-78.4°C) = 3.93 × 10³ J

where

c(g): specific heat capacity of the gas

Total heat required

Q₁ + Q₂ + Q₃ + Q₄ = 4.83 × 10³ J + 2.28 × 10⁴ J + 40.5 × 10³ J + 3.93 × 10³ J = 7.21 × 10⁴ J

3 0
3 years ago
Calculate: (a) the weight (in lbf) of a 30.0 lbm object. (b) the mass in kg of an object that weighs 44N. (c) the weight in dyne
belka [17]

Answer:

a) 965,1 lbf

b) 4,5 kg

c) 1,33 * 10^6 dynes

Explanation:

Mass of an object refers to the amount of mattter it cotains, it can be expressed it gr, kg, lbm, ton, etc.

Weight of an object refers to a force, and is the measurement of the pull of gravitiy on an object. It may be definide as the mass times the acceleration of gravity.

                                        w=mg

In Planet Earth, the nominal "average" value for gravity is 9,8 m/s² (in the International  System) or 32,17 ft/s² (in the FPS system).

To solve this problem we'll use the following conversion factors:

1 lbf = 1 lbm*ft/s²

1 N = 1 kg*m/s²

1 dyne = 1 gr*cm/s²   and 1 N =10^5 dynes

1 ton = 907,18 kg

1 k = 1000 gr

a) m = 30 lbm

w = 30 lbm * 32,17 ft/s^{2} = 965, 1 \frac{lmb*ft}{s^{2} } = 965,1 lbf

b) w = 44 N

First, we clear m of the weight equation and then we replace our data.

m = \frac{w}{g} = \frac{44 N}{9,8 \frac{m}{{s}^{2}} } = 4,5 kg

c) m = 15 ton

m=15 ton * \frac{907,18 kg}{1 ton} = 13607,7 kg \\ w = mg = 13607,7 kg * 9,8 m/s2 = 133355,5 N * \frac{10^{5} dynes }{1 N} = 1,33 * 10^{6}dynes

4 0
3 years ago
Other questions:
  • [TG.05]Which of these statements best explains why P waves arrive earlier than S waves at the seismic station?
    12·2 answers
  • Which statement is true about limiting reactants?
    12·2 answers
  • Is Weight Measurement a phenomenon?
    10·2 answers
  • HELP PLEASE
    9·2 answers
  • 2. A 0.45g sample of mineral ore is analyzed for chromium and found to contain
    13·1 answer
  • When energy changes forms there is always some thermal energy that is produced that cannot be used. what type of energy is it?
    6·1 answer
  • A blacksmith partners with a team of chemistry and physics graduate students to
    10·2 answers
  • Can somebody help me with this please
    9·1 answer
  • 2 KCIO3= 2 KOT + 3 O2<br>is balanced?​
    14·1 answer
  • A 10.0 mL sample of 5.00M HCl is diluted until its final concentration is 0.215M. What is the final volume of the diluted soluti
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!