This concept is inferred from quantum mechanics. According to quantum mechanics, electrons can absorb or emit energy by a discrete amount of energy called quanta. This follows from the two contradicting theory of wave-particle theory of light. It was widely accepted already that light behaves like a wave. However, questions are still unanswered on why electromagnetic waves emit or absorb light in specific frequencies. Until Planck proposed his equation: E = hν, where E is the energy, h is called the Planck's constant and ν is the frequency.
In this equation, it signifies that increase energy is progressing at discrete amounts of frequencies and this constant is denoted by h.
Work = force x distance
So we are looking for something related to displacement.
The work done must also be done in the same direction, parallel to the displacement, and therefore in the same direction of the motion as well.
So:
In order to do work, the force vector must be in the same direction as the displacement vector and the motion.
Answer:
focal length depends on the radius of curvature, the refractive index of lens material, and the medium's refractive index in which the lens is placed
Answer: Dynamic - Static Flexibility
Explanation:
<span>a. The magnitude of the vector is doubled as well.
Let's say we have a 2-dimensional vector with components x and y.
It's magnitude lâ‚ is given by:
lâ‚ = âš(x² + y²)
If we double the components x and y, the new magnitude lâ‚‚ is:
lâ‚‚ = âš((2x)² + (2y²))
With a bit of algebra...
lâ‚‚ = âš(4x² + 4y²)
lâ‚‚ = âš4(x² + y²)
lâ‚‚ = 2âš(x² + y²)
We can write the new magnitude lâ‚‚ in terms of the old magnitude lâ‚.
lâ‚‚ = 2lâ‚
Therefore, the new magnitude is double the old one.
It should be clear that this relationship applies to 3D (and 1D) vectors as well.
b. The direction angle is unchanged.
The direction angle θ₠for a 2-dimensional vector is given by:
θ₠= arctan(y / x)
If we double both components, we get:
θ₂ = arctan(2y / 2x)
θ₂ = arctan(y / x)
θ₂ = θâ‚
The new direction angle is the same as the old one.</span>