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OverLord2011 [107]
3 years ago
12

A particle with a charge of 4.4 * 10^-5 C is released in an electric field whose magnitude is 750 N/C. What is the force that th

e field exerts on the particle?
Physics
1 answer:
padilas [110]3 years ago
4 0

Answer:

F = 3.3×10^ -2 N

.................

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A 2.0-kilogram laboratory cart is sliding across a horizontal frictionless surface at a constant velocity of 4.0 meters per seco
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Does mechanical advantage have units? Explain your answer.
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Read 2 more answers
A force F with arrow applied to an object of mass m1 produces an acceleration of 3.10 m/s2. The same force applied to a second o
Bas_tet [7]

Answer:

(a) The value of the ratio m₁/m₂ is 0.581

(b)  the acceleration of the combined masses is 1.139 m/s²

Explanation:

Given;

The acceleration of force applied to M₁, a₁ = 3.10 m/s²

The same force applied to M₂ has acceleration, a₂ = 1.80 m/s²

Let this force = F

According Newton's second law of motion;

F = ma

(a) the value of the ratio m₁/m₂

since the applied force is same in both cases,  M₁a₁ = M₂a₂

\frac{m_1}{m_2} = \frac{a_2}{a_1} \\\\\frac{m_1}{m_2} = \frac{1.8}{3.1} \\\\\frac{m_1}{m_2} = 0.581

(b) the acceleration of m₁ and m₂ combined as one object under the action force F

F = ma

a = \frac{F}{M} \\\\a =  \frac{F}{m_1 + m_2} \\\\a = \frac{F}{0.581m_2 + m_2}\\\\a = \frac{F}{1.581m_2}

But, m_2 = \frac{F}{a_2} \\\\a = \frac{F}{1.581m_2} =  \frac{F*a_2}{1.581F} \\\\a = \frac{a_2}{1.581} \\\\a = \frac{1.8}{1.581} = 1.139 \ m/s^2

Therefore, the acceleration of the combined masses is 1.139 m/s²

5 0
3 years ago
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