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Vinil7 [7]
3 years ago
5

A 2 kg book is pushed from rest to a final velocity of 3 m/s. The book travels 2 m. How much force was the book pushed with

Physics
2 answers:
Studentka2010 [4]3 years ago
6 0

Explanation:

first you have to find accelerarion, it is given that the initial velocity(u) is 3 m/s, distance travelled(s) be 2m finall it came to rest so final velocity be 0m/s

now using the 3rd law of motion

v^2=u^2+2as

0=9+2a2

a= -9/4m/s^2

now force=mass×accelration

=2kg×(-9/4)m/s^2

=4.5 N

4.5 newton force applied on the book!

✌️:)

Natali5045456 [20]3 years ago
6 0

Answer:

4.5N

Explanation:

Step 1:

Data obtained from the question:

Mass (m) = 2Kg

Initial velocity (U) = 0

Final Velocity (V) = 3m/s

Distance travelled (s) = 2m

Force (F) =?

Step 2:

Determination of the acceleration of the book. This is illustrated below:

Using V^2 = U^2 + 2as, the acceleration (a) can be obtained as follow:

V^2 = U^2 + 2as

3^2 = 0 + 2 x a x 2

9 = 4a

Divide both side by the coefficient of a i.e 4

a = 9/4

a = 2.25m/s2

Step 3:

Determination of the force applied. This is illustrated below:

Force = Mass x Acceleration

F = m x a

F = 2 x 2.25

F = 4.5N

Therefore, a force of 4.5N was used to push the book.

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If a force of 250N is applied to a piano being pushed up a ramp at an angle of 18degrees above the horizontal, what force is bei
klasskru [66]

answer

77.25 N

explanation

(look at picture for free body diagram)

the force on the piano has both vertical and horizontal components, and since the questions asks about the force to lift the piano, we want to find the vertical component

we can use trigonometry where sinA = opposite/hypotenuse

A = 18 degrees

hypotenuse = 250 N

sin18 = opposite (vertical component) / 250

vertical component = sin18 * 250

= 77.25 N

4 0
3 years ago
1. Differentiate between speed and velocity.
Mazyrski [523]

Answer:

1. Speed and velocity both involve a numeric rate describing the distance traveled by a body in a unit of time. However, speed describes the rate of a body traveling in any direction in a unit of time, while velocity describes the rate of a body traveling in a particular direction in a unit of time.

2. Answers may vary, but should resemble the following:

Average velocity explains the velocity the body traveled overall, not taking into consideration each spot in the trip. If a car moves at 65 km/h on average, it may have slowed down for some parts and sped up for others. Overall though, it would have made a certain distance of travel within a specified unit of time that totals the average velocity of 65 km/h.

Instantaneous velocity explains the velocity of a body at a particular instant of the trip. The instantaneous velocity of a car stopped at a stop sign would be 0 m/s even if it was moving before and will continue to move after this stop. The velocity at that particular instant is the instantaneous velocity.

Uniform velocity is when the distance being covered is changing uniformly with time. For example, if a car moves 20 km every 30 minutes and continues to do so in the same direction, it's traveling with a uniform velocity.

3. a=v2−v1t

a=20 m/s−60 m/s6 s

a=−406

a = –6.7 m/s2

4. v2 = v1 + at

v2 = 14 m/s + (3 m/s2 × 6 s)

v2 = 14 + 18

v2 = 32 m/s

5. v=st

v=375 km5 h

v = 75 km/h  

6. First, convert the minutes to seconds. Since there are 60 seconds in one minute, multiply:

60 × 15 (minutes) = 900 seconds

s = v × t

s = 6 m/s × 900 s

s = 5,400 m

7. t=sv

t=80 km35 km/hr

t = 2.29 hr

8. a=v2−v1t

a=50 m/s−15 m/s4 s

a=35 m/s4 s

a = 8.75 m/s2

9. vav=v1+v22

vav=15 m/s+50 m/s2

vav=65 m/s2

vav = 32.5 m/s

10. a=v2−v1t

a=0 m/s−11.5 m/s3.5 s

a = –3.29 m/s2

Explanation:

7 0
3 years ago
The electron dot diagram shows the arrangement of dots without identifying the element.
olasank [31]

<em>Answer: </em>tellurium (Te)

<em>atomic number = 52 ,</em>

<em>Number of energy levels = 5;</em>

              First energy level = 2

         Second energy level = 8

             Third energy level = 18

           Fourth energy level = 18

               Fifth energy level = 6

<em>In this electron configuration, 0uter most electrons are 6.</em>


5 0
3 years ago
Read 2 more answers
A 3.0-kg mass and a 5.0-kg mass hang vertically at the opposite ends of a very light rope that goes over an ideal pulley. If the
AleksAgata [21]

Answer:

acceleration = 2.4525‬ m/s²

Explanation:

Data: Let m1 = 3.0 Kg, m2 = 5.0 Kg, g = 9.81 m/s²

Tension in the rope = T

Sol: m2 > m1

i) for downward motion of m2:

m2 a = m2 g - T

5 a = 5 × 9.81 m/s² - T  

⇒ T = 49.05‬ m/s² - 5 a     Eqn (a)‬

ii) for upward motion of m1

m a = T - m1 g

3 a = T - 3 × 9.8 m/s²

⇒ T =  3 a + 29.43‬ m/s²   Eqn (b)

Equating Eqn (a) and(b)

49.05‬ m/s² - 5 a = T =  3 a + 29.43‬ m/s²

49.05‬ m/s² - 29.43‬ m/s² = 3 a + 5 a

19.62 m/s² = 8 a

⇒ a = 2.4525‬ m/s²

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3 years ago
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