Kinetic Energy - What does it depend on?

The specific latent heat of fusion of ice is 3.3×105J/kg

Dima020 [189]

Vai c fude
..........................................................................

7 0

4 years ago

The energy of an electromagnetic wave changes proportionally to which

ozzi

Answer:

D. Frequency

Explanation:

The energy of an electromagnetic wave is proportional to frequency, mathematically it is expressed as;

E ∝ f

E = hf

where;

h is Planck's constant = 6.626 x 10⁻³⁴ Js

The equation above can also be expanded to;

$E = hf = h \frac{c}{\lambda}$

where;

c is speed of light = 3 x 10⁸ m/s

λ is the wavelength of the electromagnetic wave

Since the speed of light is constant, we can conclude that the energy of the electromagnetic wave is directly proportional to its frequency and inversely proportional to its wavelength.

Therefore, the correct option for direct proportionality is FREQUENCY

8 0

3 years ago

Pretend you (80 kg) are making repairs on the outside of the International Space Station. You are floating 20 meters away from t

djyliett [7]

Answer:

32 seconds

Explanation:

m1 = 80 kg

m2 = 10 kg

v2 = 5m/s

According to the property of conservation of momentum, assuming that both you and the bag are stationary before the safety rope comes lose:

$m_{1} v_{1} =m_{2} v_{2} \\80v_{1} =10*5 \\v_{1} = 0.625\ m/s$

Since the space station is 20 meters away, the time taken to reach it is given by:

$t = \frac{20}{0.625}\\t=32\ s$

It takes you 32 seconds to reach the station.

7 0

3 years ago

A polarized light that has an intensity I0 = 52.0 W/m² is incident on four polarizing disks whose planes are parallel and center

IceJOKER [234]

Answer:

The transmitted intensity through all polarizers = 34.73

Explanation:

Given :

Incident intensity = $52 W/m^2$

Angle between the transmission axis and polarizer optic axis = 18°

According to the malus law, when unpolarized or polarized light passes through polarizing disk, the intensity of the transmitted light is directly proportional to the square of the cosine of angle between the transmission axis and polarizer optic axis.

∴ $I = I' cos^2\alpha$

Where $I=$ transmitted intensity, $I'=$ incident intensity, $\alpha =$ angle between the transmission axis and polarizer optic axis.

Here, there are four polarizing disks so that.

from first disk,

∴ $I$ ₁ $= 52 (cos)^2$ 18°

= $52$ × $0.904$

= $47.01$

Now $I$ ₁ behave as an incident light for second polarizer so we only multiply

$cos^218$ term

so we write,

∴ $I$ ₂ = $47.01$ × $0.904$

$= 42.495$

From third polarizer,

∴ $I$ ₃ = $42.495$ × $0.904$

$= 38.415$

From forth polarizer,

∴ $I$ ₄ = $38.415$ × $0.904$

$= 34.73$

Therefor, the the transmitted intensity through forth polarizer = 34.73 $W/m^2$ .

5 0

3 years ago

By Ohm's Law, if I have a well working circuit and I swap out the battery for a new battery which has double the Voltage drop, b

svet-max [94.6K]

Answer:

current would double

Explanation:

According To Ohm's Law, the current in a conducting wire depends on the voltage drop across the two ends of the wire. It can be expressed as:

I ∝ V

⇒ V = I R

where, R is the resistance and proportionality constant.

In the given case, the resistance of the circuit remains same while the voltage drop has increased to twice the initial value by changing the battery. This will the cause the current to double as well from its previous value.

6 0

3 years ago