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3 years ago

Answer the following question

Physics

1 answer:

Ray Of Light [21]3 years ago

5 0

Answer:

A) OA, AB, BC

B) 25m/s^2

C) see explanation

D) 25

E) Rest

Explanation:

From the Velocity time graph shown:

The positive slope = OA ; This is positive because, it is the point of uniform acceleration on the graph.

Constant slope = AB, the slope here is constant because, AB on the graph is the point of constant velocity.

-ve slope = BC

B) Acceleration of body in path OA.

Acceleration = change in Velocity / time

Acceleration = (150 - 0) / 6

Acceleration = 150/6 = 25m/s^2

C) Path AB is Parallel to the because it marks the period of constant velocity (that is Velocity does not increase or decrease during the time interval).

D) Length of BC

BC corresponds to the distance moved, that velocity / time

Velocity = 150 ; time = 6

Therefore Distance (BC) = 150/6 = 25

E.) Velocity =0 ; Hence body is at rest

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Answer:

(a) Fₓ = 0 N

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Explanation:

The magnitude of the force will remain the same in each case, which is given as follows:

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F = force = ?

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Therefore,

F = (4.54 kg)(2 m/s²)

F = 9.08 N

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(a)

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For upward direction the force will be positive:

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Fₓ = 0 N

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3 years ago

The orbits of all the planets in the solar system are slightly elliptical with the exception of _______.

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Answer:

There is no exception to this. all planets have some eccentricity. it is physically impossible to have an orbit without any eccentricity. However, venus's orbit has the lowest (0.007) eccentricity (closest to circular) so that could be your answer.

Mercury's orbit's eccentricity 0.2

Venus's orbit's eccentricity 0.007 (this is the lowest so it may be your answer)

Earth's orbit's eccentricity 0.0167

Mars's orbit's eccentricity 0.0934

Jupiter's orbit's eccentricity 0.0489

Saturn's orbit's eccentricity 0.0565

Neptune's orbit's eccentricity 0.009

Uranus's (yur,in,iss) orbit's eccentricity 0.0457

Pluto's (not really a planet) orbit's eccentricity 0.2444 (very high)

hope it helped.

Wbob3914

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3 years ago

A rock with a mass of 2.0 kg falls from a cliff. At a height of 5.0 meters, its velocity is 6.0 m/s. What is the mechanical ener

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Answer : The mechanical energy of the rock is, 134 J

Solution :

As we know that the mechanical energy is equal to the sum of the kinetic energy and the potential energy.

The formula used for mechanical energy is,

$M.E=K.E+P.E\\\\M.E=(\frac{1}{2}mv^2)+(mgh)$

where,

M.E = mechanical energy

K.E = kinetic energy

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m = mass of an object = 2 Kg

v = velocity of an object = 6 m/s

h = height = 5 m

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Now put all the given values in the above formula, we get the mechanical energy of the rock.

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Therefore, the mechanical energy of the rock is, 134 J

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