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dolphi86 [110]
4 years ago
9

Which equation is the correct translation of the following statement?

Mathematics
2 answers:
xxMikexx [17]4 years ago
3 0

Answer: x - 4 = 9  (x will equal 13)

What I did was since 4 is less than 13 we could use 13-4 since 4 is less than 13.

13-4 will get u 9 so that x will equal 13

13-4=9

QveST [7]4 years ago
3 0

Answer:

Answer: x - 4 = 9  

Step-by-step explanation:

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The area of a semicircle is A=1/2(3.14)r^2 solve for r
Inessa05 [86]
First divide bot sides of the formula by 1/2(3.14):-

2A / 3.14 =  r^2

r = sqrt (2A/3.14)
7 0
3 years ago
|2x-8| + 3 = 5 two solutions
Delicious77 [7]

Answer:

The two solutions are 5 and 3

Step-by-step explanation:

The equation of the absolute has two solutions because IxI = a means x = a and x = -a

Let us solve the question using this fact

∵ I2x - 8I + 3 = 5

→ Subtract 3 from both sides

∴ I2x - 8I + 3 - 5 = 5 - 3

∴ I2x - 8I = 2

By using the fact above

→ 1st solution

∵ 2x - 8 = 2

→ Add 8 to both sides

∴ 2x - 8 + 8 = 2 + 8

∴ 2x = 10

→ Divide both sides by 2 to find x

∴ x = 5

→ 2nd solution

∵ 2x - 8 = -2

→ Add 8 to both sides

∴ 2x - 8 + 8 = -2 + 8

∴ 2x = 6

→ Divide both sides by 2 to find x

∴ x = 3

∴ The two solutions are 5 and 3

6 0
3 years ago
3x^2-12x-21=0 solve by completing the square
morpeh [17]

Answer:

x = 2 ± √11 (I believe)

Step-by-step explanation:

3 0
3 years ago
I-Ready
Alex Ar [27]

Answer:

23/7 or 3 2/7

Step-by-step explanation:

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4 0
2 years ago
Luke and isabella make scale drawings.The scale from isabella's drawing is 6 m to 3 cm. The height of the fountain in isabella's
den301095 [7]

Answer:

The answer is "2.5 \ cm"

Step-by-step explanation:

While Luke is 5m to 2cm in size, it implies that every 2cm to Luke's drawing is 5m in real life. That real pond width must therefore be 5 m, given the fountain's width is 2 cm. As shown in the illustration, the step size for IsabelLa from the illustration to real life is \frac{6}{3} =2, which makes it simple to multiply any measure in the cm of her illustration by 2 to accomplish the exact size in m. So, in another direction around, they just have to divide the value by 2, instead of the divide from reality for drawing. So if the actual worth is 5m, it ought to be \frac{5}{2} = 2.5 \ cm in its width.

7 0
3 years ago
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