Non metals tend to have higher ionization energies
Answer:
![1.18454\times 10^{-19}\ Pa](https://tex.z-dn.net/?f=1.18454%5Ctimes%2010%5E%7B-19%7D%5C%20Pa)
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
m = Mass of bullet = ![2.6\times 10^{23}\ kg](https://tex.z-dn.net/?f=2.6%5Ctimes%2010%5E%7B23%7D%5C%20kg)
r = Radius of barrel = ![2.8\times 10^{23}\ m](https://tex.z-dn.net/?f=2.8%5Ctimes%2010%5E%7B23%7D%5C%20m)
![v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{370^2-0^2}{2\times 0.61}\\\Rightarrow a=112213.11475\ m/s^2](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as%5C%5C%5CRightarrow%20a%3D%5Cdfrac%7Bv%5E2-u%5E2%7D%7B2s%7D%5C%5C%5CRightarrow%20a%3D%5Cdfrac%7B370%5E2-0%5E2%7D%7B2%5Ctimes%200.61%7D%5C%5C%5CRightarrow%20a%3D112213.11475%5C%20m%2Fs%5E2)
Pressure is given by
![P=\dfrac{F}{A}\\\Rightarrow P=\dfrac{ma}{\pi r^2}\\\Rightarrow P=\dfrac{2.6\times 10^{23}\times 112213.11475}{\pi (2.8\times 10^{23})^2}\\\Rightarrow P=1.18454\times 10^{-19}\ Pa](https://tex.z-dn.net/?f=P%3D%5Cdfrac%7BF%7D%7BA%7D%5C%5C%5CRightarrow%20P%3D%5Cdfrac%7Bma%7D%7B%5Cpi%20r%5E2%7D%5C%5C%5CRightarrow%20P%3D%5Cdfrac%7B2.6%5Ctimes%2010%5E%7B23%7D%5Ctimes%20112213.11475%7D%7B%5Cpi%20%282.8%5Ctimes%2010%5E%7B23%7D%29%5E2%7D%5C%5C%5CRightarrow%20P%3D1.18454%5Ctimes%2010%5E%7B-19%7D%5C%20Pa)
The pressure of the expanding gas is ![1.18454\times 10^{-19}\ Pa](https://tex.z-dn.net/?f=1.18454%5Ctimes%2010%5E%7B-19%7D%5C%20Pa)
As per bernoulli's principle
![P_1 + \frac{1}{2}\rho v_1^2 = P_2 + \frac{1}{2}\rho v_2^2](https://tex.z-dn.net/?f=P_1%20%2B%20%5Cfrac%7B1%7D%7B2%7D%5Crho%20v_1%5E2%20%3D%20P_2%20%2B%20%5Cfrac%7B1%7D%7B2%7D%5Crho%20v_2%5E2)
here
= pressure upwards
= pressure downwards
= velocity of air upwards
= velocity of air downwards
now from this equation we can say that the pressure difference will be
![P_1 - P_2 = \frac{1}{2}\rho v_2^2 - \frac{1}{2}\rho v_1^2](https://tex.z-dn.net/?f=P_1%20-%20P_2%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Crho%20v_2%5E2%20-%20%5Cfrac%7B1%7D%7B2%7D%5Crho%20v_1%5E2)
now the force due to this pressure difference will be
![F = (P_1 - P_2)A](https://tex.z-dn.net/?f=F%20%3D%20%28P_1%20-%20P_2%29A)
so this is the above force which is given above
The uncertainty of the heavy object if the scale remains constant is 0.24 lbs.
<h3>What is uncertainty in measurement?</h3>
- This is the error associated in an attempt measure the object accurately.
The percent uncertainty in measuring the light weight object is calculated as follows;
![= \frac{0.034}{11} \times 100\%\\\\= 0.309\%](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B0.034%7D%7B11%7D%20%5Ctimes%20100%5C%25%5C%5C%5C%5C%3D%200.309%5C%25)
The uncertainty of the heavy object if the scale remains constant is calculated as follows;
![= \frac{0.309}{100} \times 78.0 \ lbs\\\\= 0.24 \ lbs](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B0.309%7D%7B100%7D%20%5Ctimes%2078.0%20%5C%20lbs%5C%5C%5C%5C%3D%200.24%20%5C%20lbs)
Learn more about percent uncertainty here: brainly.com/question/5493941