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irina [24]
4 years ago
5

A 10-meter rope is lying on the floor and has a mass force of 20 N. How much work is required to raise one end of the rope to a

height of 5 meters?
Physics
1 answer:
VMariaS [17]4 years ago
7 0
Answer:10N

Explanation: I think
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A rope is vibrating in such a manner that three equal-length segments are found to be vibrating up and down with 321 complete cy
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<u>2.48 m</u> is the length of the rope.

Explanation:

Cycle period is 321

Time is 20 second

Wave travels at speeds = 26.4 m/s

We know that,

\text { Frequency }=\frac{1}{T} \text { (For one cycle) }

Frequency required for 321 complete cycle in 20 seconds is

\text { Frequency }(f)=\frac{321}{20}

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We know that,

\text { Wavelength }=\frac{\text { wave velocity }}{\text { frequency }}

\lambda=\frac{v}{f}

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v = wave velocity, the "speed" that waves are moving in a direction (m/s)

f = frequency, (cycles/ or Hz)

\lambda=\frac{26,4}{16.05}

λ = 1.65 m

As per given question "length of the rope has three equal length segment"

\mathrm{Length of the rope}=\frac{3}{2} \lambda

\mathrm{Length of the rope }=\frac{3}{2} \times 1.65

\mathrm{Length of the rope}=1.5 \times 1.65

Length of the rope = 2.48 m

Therefore, length of the rope is <u>2.48 m.</u>

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