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vodka [1.7K]
3 years ago
9

The weight of your car will also affect its _____.

Physics
2 answers:
Zolol [24]3 years ago
4 0

Answer:

Stopping distance

Explanation:

Mekhanik [1.2K]3 years ago
3 0

Answer:

Stopping distance

Explanation:

The higher the weight of a car, the higher its stopping distance will be. This is because the energy of motion increases as weight increases, making it be harder and take longer to stop your vehicle. 18-wheelers are a great example of this, because they travel at the same speed of regular cars but take much longer to stop.

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A car is travelling with a velocity of 10 m/s and has a mass of 550 kg. The<br> car has<br> energy.
Elenna [48]

Answer: The car has a kinetic energy (because it's in motion) of:  27500J

Explanation:

Formula: E=\frac{1}{2}mv^2

E=\frac{1}{2}mv^2

E=\frac{1}{2}(550kg)(10m/s)^2

E=\frac{1}{2}(550kg)(100m^2/s^2)

E=\frac{1}{2}(55000J)\\E=27500J

3 0
4 years ago
What distance will a car cover while uniformly accelerating from 12m/s to 26m/in 14 seconds​
VikaD [51]

Answer:

Distance = 266m

Explanation:

6 0
4 years ago
A 120-kg object and a 420-kg object are separated by 3.00 m At what position (other than an infinitely remote one) can the 51.0-
djverab [1.8K]

Answer:

1.045 m from 120 kg

Explanation:

m1 = 120 kg

m2 = 420 kg

m = 51 kg

d = 3 m

Let m is placed at a distance y from 120 kg so that the net force on 51 kg is zero.

By use of the gravitational force

Force on m due to m1 is equal to the force on m due to m2.

\frac{Gm_{1}m}{y^{2}}=\frac{Gm_{2}m}{\left ( d-y \right )^{2}}

\frac{m_{1}}{y^{2}}=\frac{m_{2}}{\left ( d-y \right )^{2}}

\frac{3-y}{y}=\sqrt{\frac{7}{2}}

3 - y = 1.87 y

3 = 2.87 y

y = 1.045 m

Thus, the net force on 51 kg is zero if it is placed at a distance of 1.045 m from 120 kg.

6 0
4 years ago
As a pole of a 2nd-order discrete-time system moves away from the origin in the z-plane, while its phase remains constant, the d
Rudik [331]

Answer:

False

Explanation:

When the location of the poles changes in the z-plane, the natural or resonant frequency (ω₀) changes which in turn changes the damped frequency (ωd) of the system.

As the poles of a 2nd-order discrete-time system moves away from the origin then natural frequency (ω₀) increases, which in turn increases damped oscillation frequency (ωd) of the system.

ωd = ω₀√(1 - ζ)

Where ζ is called damping ratio.

For small value of ζ

ωd ≈ ω₀

4 0
3 years ago
What are generated at transform fault plate boundaries?
tankabanditka [31]

Answer: The Earth's layer, which has the covering and layer, is made of a progression of things, or structural plates, that creep after some time. Along these lines, at intersecting limits, mainland outside is made and maritime covering is devastated. 2 plates slippy past each other structures a redesign plate limit.

5 0
3 years ago
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