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My name is Ann [436]
2 years ago
11

In surveying , supposing we can not pull the tape because it is passing through a shallow river. What will i do to obtain an acc

urate distance?​
Engineering
1 answer:
natulia [17]2 years ago
7 0

Answer:

Hold the tape in place and go down to the end.

Explanation:

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A spherical tank is being designed to hold 10 moles of carbon dioxide gas at an absolute pressure of 5 bar and a temperature of
lesya692 [45]

Answer:

r=0.228m

Explanation:

The equation that defines the states of a gas according to its thermodynamic properties is given by the general equation of ideal gases

PV=nRT

where

P=pressure =5bar=500.000Pa

V=volume

n=moles=10

R = universal constant for ideal gases = 8.31J / (K.mol)

T=temperature=80F=299.8K

solvig For V

V=(nRT)/P

V=(\frac{(10)(8.31)(299.8)}{500000} )\\V=0.0498m^3

we know that the volume of a sphere is

V=\frac{4\pi r^3}{3} \\

solving for r

r=\sqrt[3]{ \frac{3 V}{4\pi } }

solving

r=\sqrt[3]{ \frac{3 (0.049)}{4\pi } }\\r=0.228m

4 0
3 years ago
Can i make an engine with magnets?
Phantasy [73]

Answer:

No, because Scientists and inventors alike have attempted to use permanent magnets alone to drive a motor. A permanent magnet motor would not produce energy and would not be a perpetual motion machine.

5 0
3 years ago
XYZ Company purchased a new machine on January 1, 2020 for $160,000. The machine was assigned a 40-year life and a $3,000 residu
AlekseyPX

Answer:

Accumulated depreciation at December 32, 2023 = 29679

Explanation:

machine = 160000

useful life = 40 years

residual value = 3000

straight-line depreciation rate = (160000 - 3000) ÷ 40

                                    = 3925 per year

Annual depreciation rate = 100% ÷ 40 = 2.5%

double-declining rate = 2 × 2.5% = 5%

Depreciation for 2020 = 5% × 160000 = 8000

Depreciation for 2021 = 5% × (160000 - 8000) = 7600

Depreciation for 2022 = 5% × (160000 - 8000 - 7600) = 7220

Depreciation for 2023 = 5% × (160000 - 8000 - 7600 - 7220) = 6859

Accumulated depreciation at December 32, 2023

                    = 8000 + 7600 +7220 + 6859

                    =  29679

4 0
3 years ago
A semiconductor diode has the following parameters: Is = 4.0×10-13 Amps, n = 1.35, and is operated at a temperature of T = 270K.
andrew-mc [135]

Answer:

V_T=0.02328V\\I=7.77\times 10^{-5} A \\V_D=0.77V

Explanation:

Let's use Shockley ideal diode equation which relates the current intensity and the potential difference:

I=I_S (e^{\frac{V_D}{nV_T} } -1)

Where:

I=Diode\hspace{3}current\\I_S=Reverse\hspace{3}bias\hspace{3}saturation\hspace{3}current\\V_D=Voltage\hspace{3}across\hspace{3}the\hspace{3}diode\\V_T=Thermal\hspace{3}voltage\\n=Ideality\hspace{3}factor

Thermal voltage at any temperature it is a known constant defined by:

V_T=\frac{kT}{q}

Where:

k= Boltzmann\hspace{3}constant \approx1.38\times 10^{-23} \\T=Absolute\hspace{3}temperature\\q=Charge\hspace{3}of\hspace{3}an\hspace{3}electron \approx 1.6\times 10^{-19} C

(a)

Using the data provided:

V_T=\frac{(1.38\times 10^{-23})*(270) }{1.6\times 10^{-19} }= 0.0232875V

(b)

Using the data provided and Shockley ideal diode equation

I=(4\times 10^{-13} )*(e^{\frac{0.6}{1.35*0.0232875} }-1)=7.773505834\times10^{-5}\approx 7.77  \times10^{-5}A\\I\approx0.0777mA

(c) Let's isolate V_D from Shockley ideal diode equation:

I=I_S (e^{\frac{V_D}{nV_T} } -1)\\\\Multiply\hspace{3}both\hspace{3}sides\hspace{3}by\hspace{3}I_S\\\\\ \frac{I}{I_S} = e^{\frac{V_D}{nV_T} } -1\\\\Add\hspace{3}1\hspace{3}both\hspace{3}sides\\\\

\frac{I}{I_S} +1 =e^{\frac{V_D}{nV_T} } \\\\Take\hspace{3}the\hspace{3}natural\hspace{3}logarithm\hspace{3}of\hspace{3}both\hspace{3}sides\\\\\frac{V_D}{nV_T} =log(\frac{I}{I_S} +1) \\\\Multiply\hspace{3}both\hspace{3}sides\hspace{3}by\hspace{3}nV_T\\\\V_D=nV_T*log(\frac{I}{I_S} +1)

Finally, using the data provided:

V_D=(1.35)(0.0232875)*log(\frac{20\times 10^{-3} }{4\times 10^{-13} }+1)=0.77448729\approx 0.77V

7 0
3 years ago
What can your employer do to protect you from overhead power lines?
Kryger [21]

Answer:

Have the company install insulated sleeves over powerlines.

Explanation:

6 0
3 years ago
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