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Ber [7]
3 years ago
10

Explain the difference between the reactants and products of a chemical reaction

Chemistry
2 answers:
7nadin3 [17]3 years ago
6 0

Reactants are the starting substances and products are the ending substances in a chemical reaction.

The atoms in reactants are arranged one way and are rearranged in a different way to form the products (in other words, reactants are chemically different from products).

The properties of reactants differ from the properties of products. Good answer for E.DG.

Degger [83]3 years ago
3 0

Answer:

Reactants are the starting substances and products are the ending substances in a chemical reaction.

The atoms in reactants are arranged one way and are rearranged in a different way to form the products (in other words, reactants are chemically different from products).

The properties of reactants differ from the properties of products.

Explanation:

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The molecular formula shows the exact number of molecules. Therefor, the empirical formula is the simplest formula of the molecular formula
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3 years ago
What type of chemical bond holds the na+ and cl- ions together in table salt?
fredd [130]

<em>The bond between Na + and Cl- ions is an ionic bond</em>

<em>To achieve stability, atoms with low ionization energy such as Na atoms will release electrons and bind to atoms with high-affinity energy such as Cl atoms</em>

\boxed{\boxed{\bold{Further~explanation}}}

Atoms have different stability. Unstable atomic atoms will try to form stable electron configurations like those of noble gases. Where noble gases have the number of outer electrons 2 or 8

The formation of electron configurations such as noble gases can be done by forming shared ions or electron pairs

Atoms with high ionization energy and atoms that are difficult to draw electrons will form bonds with shared electron pairs (electrons can be from one atom or two atoms attached)

In forming ions, atoms will release or attract electrons

Ion bonds occur because atoms that have low ionization energy (easily release electrons) form a + ion, and these electrons are bound by atoms that have large affinity energy (easily pulling electrons)

Generally, ionic bonds occur in metal and nonmetallic elements. Metal elements have low ionization energy and non-metallic elements have a high electron affinity

In Na atoms, to achieve stability, Na will release one electron so that it has an electron configuration like noble gas Ne

Na: 2 8 1

Ne: 2 8

so that it becomes a Na + ion

While the Cl atom will bind one electron, so it has an electron configuration like noble gas Ar

Cl: 2 8 7

Ar: 2 8 8

So that it becomes a Cl- ion

Finally, there will be an attractive attraction between positive ions and negative ions and NaCl is formed

So the bond between Na + and Cl- ions is an ionic bond

\boxed{\boxed{\bold{Learn~more}}}

the octet rule

brainly.com/question/6979933

a noble gas

brainly.com/question/1349717

brainly.com/question/3505291

ionic bonds and covalent bonds

brainly.com/question/2092388

Keywords: ionic and covalent bonds, the octet rule, noble gases, electron configurations

4 0
3 years ago
Read 2 more answers
3.00 L of a gas is collected at 35.0°C and 705.0 mmHg. What is the volume at STP?
makvit [3.9K]

Answer:

2.47L

Explanation:

Using the combined gas law equation as follows:

P1V1/T1= P2V2/T2

Where;

P1 = initial pressure (mmHg)

P2 = final pressure (mmHg)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

P1 = 705mmHg

P2 = 760mmHg (STP)

V1 = 3.00L

V2 = ?

T1 = 35°C = 35 + 273 = 308K

T2 = 273K (STP)

Using P1V1/T1= P2V2/T2

705 × 3/308 = 760 × V2/273

2115/308 = 760V2/273

Cross multiply

308 × 760V2 = 2115 × 273

234,080V2 = 577,395

V2 = 577,395 ÷ 234,080

V2 = 2.47L

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Answer:

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Describe how to prepare 10 ml of 5, 10, 15, and 20 micro M CV solution using a 25 microM CV stock solution
zalisa [80]
A calibration curve requires the preparation of a set of known concentrations of CV, which are usually prepared by dieting a stock solution whose concentration is known.
4 0
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