Acceleration is defined as velocity per unit time.
Here, a=acceleartion,
v=velocity=36 m/s
t=time=12 s
A car at rest ends accelerates for 12 seconds. After this time the car is going 36 m/s. So acceleration that is a=3 ms⁻².
How quickly would groundwater flow through rock high porosity and high permeability?
1 answer:
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Answer:
57.8kg
Explanation:
Potential energy is given by:
Where U is potential energy, m is mass, g is acceleration due to gravity, and h is height. Using this equation:
Answer:
a) ΔGrxn = 6.7 kJ/mol
b) K = 0.066
c) PO2 = 0.16 atm
Explanation:
a) The reaction is:
M₂O₃ = 2M + 3/2O₂
The expression for Gibbs energy is:
ΔGrxn = ∑Gproducts - ∑Greactants
Where
M₂O₃ = -6.7 kJ/mol
M = 0
O₂ = 0
b) To calculate the constant we have the following expression:
Where
ΔGrxn = 6.7 kJ/mol = 6700 J/mol
T = 298 K
R = 8.314 J/mol K
c) The equilibrium pressure of O₂ over M is: