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erica [24]
3 years ago
11

If I contain 3 moles of gas in a container with a volume of 60 liters and at a

Chemistry
2 answers:
viktelen [127]3 years ago
4 0

Answer:    n = 3.0 moles

V = 60.0 L

T = 400 K

From PV = nRT, you can find P

P = nRT/V = (3.0 mol)(0.0821 L-atm/K-mol)(400 K)/60.0L

P = 1.642 atm = 1.6 atm (to 2 significant figures)

azamat3 years ago
3 0

Answer:

P = 1246.4 mmHg

Explanation:

assuming ideal gas:

  • PV = RTn

∴ R = 0.082 atm.L/K.mol

∴ V = 60 L

∴ T = 400 K

∴ n gas = 3 mol

⇒ P = RTn / V

⇒ P = ((0.082 atm.L/K.mol)(400 K)(3 mol))/(60 L)

⇒ P = (1.64 atm)×(760 mmHg/atm)

⇒ P = 1246.4 mmHg

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PLEASE HELP!!!!!!!
dsp73

Answer: 1. 2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu

2. 3 moles of CuCl_2 : 2 moles of Al

3. 0.33 moles of CuCl_2 : 0.92 moles of Al

4. CuCl_2 is the limiting reagent and Al is the excess reagent.

5. Theoretical yield of AlCl_3 is 29.3 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Al=\frac{25.0g}{27g/mol}=0.92moles

\text{Moles of} CuCl_2=\frac{45.0g}{134g/mol}=0.33moles

The balanced chemical equation is:

2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu  

According to stoichiometry :

3 moles of CuCl_2 require = 2 moles of Al

Thus 0.33 moles of CuCl_2 will require=\frac{2}{3}\times 0.33=0.22moles  of Al

Thus CuCl_2 is the limiting reagent as it limits the formation of product and Al is the excess reagent.

As 3 moles of CuCl_2 give = 2 moles of AlCl_3

Thus 0.33 moles of CuCl_2 give =\frac{2}{3}\times 0.33=0.22moles  of AlCl_3

Theoretical yield of AlCl_3=moles\times {\text {Molar mass}}=0.22moles\times 133.34g/mol=29.3

Thus 29.3 g of aluminium chloride is formed.

5 0
2 years ago
M=<br> V=432.6 mL<br> D=8.4 g/ml
Nitella [24]

Answer:

Explanation:

M=D times V

Answer-3,633.84g

Rounded Answer (correct sig figs)- 3600g

6 0
3 years ago
About how much is one liter?
AleksAgata [21]
Look at the liter man it’s a great way to learn how much every liquid measurement is
7 0
3 years ago
Select the correct answer.
almond37 [142]

Answer:

D. 5 moles

Explanation:

C3H8 + 5O2 → 4H2O + 3CO2

            5 mol                 3 mol

So, to make 3 mol CO2    5 mol O2 are needed.

3 0
3 years ago
An aqueous solution of Calcium Chloride reacts with an aqueous solution
Tems11 [23]

Answer:

the products formed are : -

1. CaCO3 - Calcium Carbonate

2. NaCl - Sodium Chloride

Explanation:

Calcium chloride reacts with Sodium carbonate to form Calcium carbonate and Sodium chloride. this reaction is a double displacement reaction.

here's the balanced chemical equation for the above reaction : -

CaCl2 + Na2CO3 =》CaCO3 + 2 NaCl

7 0
2 years ago
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