If I contain 3 moles of gas in a container with a volume of 60 liters and at a
2 answers:
Answer: n = 3.0 moles
V = 60.0 L
T = 400 K
From PV = nRT, you can find P
P = nRT/V = (3.0 mol)(0.0821 L-atm/K-mol)(400 K)/60.0L
P = 1.642 atm = 1.6 atm (to 2 significant figures)
Answer:
P = 1246.4 mmHg
Explanation:
assuming ideal gas:
∴ R = 0.082 atm.L/K.mol
∴ V = 60 L
∴ T = 400 K
∴ n gas = 3 mol
⇒ P = RTn / V
⇒ P = ((0.082 atm.L/K.mol)(400 K)(3 mol))/(60 L)
⇒ P = (1.64 atm)×(760 mmHg/atm)
⇒ P = 1246.4 mmHg
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