Question

What is the ammount if heat in joules required to increase the temperature of a 49.5 gram sample of water from 22c to 66c

Answer 1

Answer:

9.1KJ

Explanation:

From

H= mcθ

m= mass of the water= 49.5g

c= heat capacity of water= 4.2 Jg-1

θ= temperature change= (66°C - 22°C)= 44°C

H= 49.5×4.2×44= 9.1KJ

Answer 2

What is the amount of heat, in joules, required to increase the temperature of a 49.5-gram sample of water from 22°C to 66°C?

• (1) 9100 J
• (2) 4600 J
• (3) 1400 J
• (4) 2300 J

Answer:

9100 J is the amount of heat, in joules, required to increase the temperature of a 49.5-gram sample of water from 22°C to 66°C.

Explanation:

Given: Q = ? J

mass = 49.5 g = 0.0495 kg

T1 = 22°C

T2 = 66°C

Cp = 4.18 J/Kg°C

Q = mCpΔT

Q = (4.95)(4.18)(66 - 22)

Q = 9104 J

So 9100 J is the amount of heat, in joules, required to increase the temperature of a 49.5-gram sample of water from 22°C to 66°C.