If a lever has a mechanical advantage of 5 and 50 N of force is used to lift a rock, what is the weight of the rock?

When fossil fuels are burnt, what 2 gases are given off?

Mkey [24]

Salutations!

When fossil fuels are burnt, what 2 gases are given off?

When fossil fuels are burnt, the following are one of the two gases when they are given off:

→ Carbon dioxide: Carbon dioxide is a green house gas, and plays a major role in the global warming.

→ Carbon Monoxide: Carbon monoxide is a gas that is dangerous to human beings when released.

Hope I helped (:

Have a great day!

6 0

3 years ago

What is the most likely elevation of point B?<br>a. 150 ft<br>b. 200 ft<br>c. 125 ft<br>d. 225 ft

zepelin [54]

Answer:

D

Explanation:

erm i think its 225 ft?

7 0

4 years ago

Read 2 more answers

A diffraction pattern is formed on a screen 130 cm away from a 0.420-mm-wide slit. Monochromatic 546.1-nm light is used. Calcula

notka56 [123]

Answer:

The fractional Intensity $\frac{I}{I_{max}}$ = 0.0146

Given:

wavelength of the light, $\lambda = 546.1 nm = 546.1\times 10^{-9} m$

slit and screen separation difference, D = 130 cm = 1.3 m

distance of the point from the center of the principal maximum, y = 4.10 mm = 0.041 m

slit width, d = 0.420 mm = $0.420\times 10^{-3}$

Solution:

To calculate the fractional intensity, we use the given formula:

$\frac{I}{I_{max}} = \frac{sin^{2}\delta }{\frac({\delta}{2})^{2}}$ (1)

$\delta = \frac{\pi }{\lambda}dsin\theta$

For very small angle:

$\delta = \frac{\pi dy}{\lambda D}$ (2)

where

$\delta = total phase angle$

$\theta = angle of deviation$

Using eqn (2):

$\delta = \frac{\pi \times 0.42\times 10^{-3}\times 4.1\times 10^{-3} }{546.1\times 10^{-9}\times 1.3} = 7.6202 radians$

Now, using eqn (1):

$\frac{I}{I_{max}} = \frac{sin^{2}(7.6202) }{(\frac{7.6202}{2})^{2}} = 0.0146$

4 0

4 years ago

Gunther needs a 75% concentrated solution. When making his solution at room temperature, he could only make a solution that was

jolli1 [7]

Answer:

Heat the solution, dissolve the solute, and let it cool verifying nothing settled out.

Explanation:

7 0

3 years ago

Read 2 more answers

A person is standing on a level floor. His head, upper torso, arms, and hands together weigh 458 N and have a center of gravity

Step2247 [10]

Answer:

the location of the center of gravity for the entire body is 1.08 m

Explanation:

Given the data in the question;

w1 = 458 N, y1 = 1.34 m

w2 = 120 N, y2 = 0.766 m

w3 = 89.8 N, y2 = 0.204 m

The location arrangement of the body part is vertical, locate the overall centre of gravity by simply replacing the horizontal position x by the vertical position y as measured relative to the floor.

so,

$Y_{centre of gravity}$ = (w1y1 + w2y2 + w3y3 ) / ( w1 + w2 + w3 )

so we substitute in our values

$Y_{centre of gravity}$ = (458×1.34 + 120×0.766 + 89.8×0.204 ) / ( 458 + 120 + 89.8 )

$Y_{centre of gravity}$ = 723.9592 / 667.8

$Y_{centre of gravity}$ = 1.08 m

Therefore, the location of the center of gravity for the entire body is 1.08 m

5 0

3 years ago