A 300-kg bear grasping a vertical tree slides down at constant velocity. The friction force between the
tree and the bear is
El beneficio que obtuvo es de 2 L
Answer:
Explanation:
There will be conservation of momentum along horizontal plane because no force acts along horizontal plane.
momentum of first piece = .320 kg x 2 m/s
= 0.64 kg m/s along x -axis.
momentum of second piece = .355 kg x 1.5 m/s
= 0.5325 kg m/s along y- axis .
Let the velocity of third piece be v and it is making angle of θ with x -axis .
Horizontal component of its velocity = .100 kg x v cosθ = .1 v cosθ
vertical component of its velocity = .100 kg x v sinθ = .1 v sinθ
For making total momentum in the plane zero
.1 v cosθ = 0.64 kg m/s
.1 v sinθ = 0.5325 kg m/s
Dividing
Tanθ = .5325 / .64 = .83
θ = 40⁰.
The angle will be actually 180 + 40 = 220 ⁰ from positive x -axis.
SINGLE TO RIGHT OR CENTER FIELD-On a single to center or right field the first baseman will be the cutoff to home. The shortstop will cover second base.
Explanation:
soln,
weight=600N
mass=?
gravity=9.8 m/s²
now,
- mass=weight/gravity
- mass=600/9.8
- mass=61.22kg
hope it helps.
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