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kap26 [50]
3 years ago
6

Equation of orbit under central force​

Physics
1 answer:
SOVA2 [1]3 years ago
8 0

I found this on arxsiv.org: “The central force motion between two bodies about their center of mass can be reduced to an equivalent one body problem in terms of their reduced mass m and their relative radial distance r. ... The potential V (r) from which this force is derived is also a function of r alone, F = −VV, V ≡ V (r).”

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If a train going 60 m/s hits the brakes, and it takes the train 85 seconds to stop, what is
Anvisha [2.4K]

Question :-

  • If a Train going with 60 m/s Speed hits the Brakes, and takes 85 sec to stop. What is the Acceleration of the Train ?

Answer :-

  • Acceleration of Train is 0.70 m/s² .

Explanation :-

As per the provided information in the given question, we have been given that the Speed of the Train is 60 m/s . Time taken to stop the Train is 85 sec . And, we have been asked to calculate the Acceleration of the Train .

For calculating the Acceleration , we will use the Formula :-

\bigstar \:  \:  \:  \boxed { \sf{ \: Acceleration \:  =  \:  \dfrac{v \:  -  \: u}{t} \:  }} \\

Where ,

  • V denotes to Final Velocity .
  • U denotes to Initial Velocity .
  • T denotes to Time Taken .

Therefore , by Substituting the given values in the above Formula :-

\dag \:  \:  \:  \:  \sf{Acceleration \:  =  \:  \dfrac{Final  \: Velocity \:  -  \: Initial \: Velocity}{Time} } \\

\longmapsto \:  \:  \: \sf{Acceleration \:  =  \:  \dfrac{0 \:  -  \: 60}{85} } \\

\longmapsto \:  \:  \: \sf{Acceleration \:  =  \:  \dfrac{60}{85} } \\

\longmapsto \:  \:  \: \textbf {\textsf {Acceleration \:  =  \: 0.70 }}

Hence :-

  • Acceleration = 0.70 m/s² .

\underline {\rule {210pt} {4pt}}

Note :-

  • Kindly Scroll the Screen from Right to Left for Better View .
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