Explanation:
It is given that, a robot starts from a certain point and moves east for a distance of 5.0 meters, then goes north for 3.0 meters, and then turns west for 2.0 meters.
Let east is +x, west is -x north is +y.
When it moves east for a distance of 5.0 meters, it means (5,0)
When it goes north for 3.0 meters, and then turns west for 2.0 meters, it means (0,3) +(-2,0)
(a) x-y coordinates for the resultant vector is (3,3)
(b) The magnitude of the resultant vector for the robot is given by :
Answer:
Angular displacement of the turbine is 234.62 radian
Explanation:
initial angular speed of the turbine is
similarly final angular speed is given as
angular acceleration of the turbine is given as
now we have to find the angular displacement is given as
Answer:
83.2 W/m^2
Explanation:
The radiation per unit area of a star is directly proportional to the power emitted, which is given by Stefan-Boltzmann law:
where
is the Stefan-Boltzmann constant
A is the surface area
T is the surface temperature
So, we see that the radiation per unit area is proportional to the fourth power of the temperature:
So in our problem we can write:
where
is the power per unit area of the present sun
is the temperature of the sun
is the power per unit area of sun X
is the temperature of sun X
Solving for I2, we find
Answer:
all the forces occur in pairs that if one object exerts a force on another object, then the second object exerts an equal and opposite reaction force on the first.
