Hrxn = Q reaction / mol of reaction
mol of reaction = M * V = 10 * 1 = 10 mmol = 0.01 mol
Q water = m * C * (Tf - Ti)
= (10 + 10) (4.184) (26-20) = 502.08 J
Q reaction = - Q water = -502.08 J
Hrxn = -502.08 / (0.01) = - 50208 J = - 50.21 kJ/mol
Option No. 1 at the cathode in both an electrolytic cell and a voltaic cell
Negative ion arrives at the anode, attracted by electrostatic forces, where they lose electrons. Loss of electrons is defined as oxidation.
The reverse process occur at the negative electrode, where positive ions pick up electrons. They are reduced.
HCI are less soluble in water as the temperature of the solution is increased.
With the 12.00 grams of magnesium
