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murzikaleks [220]
3 years ago
7

What forces affect kinetic energy

Physics
1 answer:
KIM [24]3 years ago
4 0
Many factors affect<span> potential and </span>kinetic energy<span>. </span>Kinetic energy<span> is </span>energy<span> in motion, while potential </span>energy<span> is </span>energy<span> that hasn't happened yet. ... </span>Kinetic energy<span> is the </span>energy<span> an object produces when moving. Due to gravity, </span>kinetic energy<span> is </span>affected <span>by the object's mass and velocity.

Hope this helps. </span>
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Help please, this is unit about work, power, force in physics.
bearhunter [10]
1 to 4 5 throu the 7 to 9 and then others are obviously to the 6 and 8
5 0
3 years ago
Calculate the energy absorbed when 13 kg of liquid water raises from 18°C to 100°C and then boils at 100°C.
Cloud [144]

Answer:

the energy absorbed is 4.477 x 10⁶ J

Explanation:

mass of the liquid, m = 13 kg

initial temperature of the liquid, t₁ = 18 ⁰C

final temperature of the liquid, t₂ = 100 ⁰C

specific heat capacity of water, c = 4,200 J/kg⁰C

The energy absorbed is calculated as;

H = mcΔt

H = mc(t₂ - t₁)

H = 13 x 4,200(100 - 18)

H = 4.477 x 10⁶ J

Therefore, the energy absorbed is 4.477 x 10⁶ J

5 0
3 years ago
When water molecules are disappearing into the air, there is a net _______?
MrRa [10]
Evaporation would be the answer.



7 0
3 years ago
A(n) 1.3 kg mass sliding on a frictionless surface has a velocity of 7.1 m/s east when it undergoes a one-dimensional elastic co
Oxana [17]

Answer: 2.12 kg

Explanation:

Since the 1.3 kg object moves to the west after the collision, the other object will move to the east after the collision.

In an elastic collision, the relative velocity after the collision is the opposite of the relative velocity before the collision. Since the 1.3 kg object’s velocity before the collision is 6.7 m/s greater than the other object, after the collision, its velocity will be 6.7 m/s less than the other object. To determine the other object’s velocity, use the following equation.

v = 1.7 – 7.1 = -5.4 m/s

The negative sign means it is moving eastward. Let’s use this number is a momentum equation to determine its mass.

Initial momentum = 1.3 * 7.1 = 9.23 east

For the 1.3 object, final momentum = 1.3 * 1.7 = 2.21 west

To determine the final momentum of the other object, add these two numbers.

Final momentum = 11.44 east

To determine its mass, use the following equation.

m * 5.4 = 11.44

m = 11.44 ÷ 5.4 = 2.12 kg

To make sure that kinetic energy is conserved, let’s round this number to 2 kg and determine the final kinetic energies.

For the 1.3 object, KE = 1/2 * 1/3* 1.7^2 = 0.48

For the 2 kg object, KE = 1/2* 2 * 5.4^2 = 29.64

Total final KE = 29.64

Initial KE = 0.5* 1.3 * 7.1^2 = 32.77

Since I rounded the mass up to 2kg, this proves that kinetic energy is conserved and the mass is correct!

3 0
3 years ago
Why is it that the weight of an object weighing 1N air, weighs more when immersed in water ?
Anni [7]
There is no "why", because that's not what happens.  The truth is
exactly the opposite. 

Whatever the weight of a solid object is in air, that weight will appear
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The object is lifted by a force equal to the weight of the fluid it displaces.
It displaces the same amount of air or water, and any amount of water
weighs more than the same amount of air.  So the force that lifts the
object in water is greater than the force that lifts it in air, and the object
appears to weigh less in the water.
4 0
3 years ago
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