Answer:
C) must be such as to follow the magnetic field lines.
Explanation:
Ampere's circuital law helps us to calculate magnetic field due to a current carrying conductor. Magnetic field due to a current forms closed loop around the current . If a net current of value I creates a magnetic field B around it , the line integral of magnetic field around a closed path becomes equal to μ₀ times the net current . It is Ampere's circuital law . There may be more than one current passing through the area enclosed by closed curve . In that case we will take net current by adding or subtracting them according to their direction.
It is expressed as follows
∫ B.dl = μ₀ I . Here integration is carried over closed path . It may not be circular in shape. The limit of this integration must follow magnetic field lines.
the term ∫ B.dl is called line integral of magnetic field.
Answer:
To find the mass using density and volume we just multiply them against each other which causes ml to cancel and just leaves us with grams which represents how much the item weights.
Therefore, our final answer is that our pencil weight 3.5 grams
<u><em>Hope this helps! Let me know if you have any questions</em></u>
To solve this problem it is necessary to apply the concepts related to the conservation of the Momentum describing the inelastic collision of two bodies. By definition the collision between the two bodies is given as:
Where,
= Mass of each object
= Initial Velocity of Each object
= Final Velocity
Our values are given as
Replacing we have that
Therefore the the velocity of the 3220 kg car before the collision was 0.8224m/s
The Volume of a Cube with a side(s) of 11.4 cm is
<span>V = s^3 </span>
<span> V = (11.4)^3 cm^3 </span>
<span> V = 1481.544 cm^3 </span>
<span> V = 1482 cm^3</span>
<span>however the Surface Area of a cube is the combined area of all the sides </span>
<span> A = 6s^2 </span>
<span> A = 6(11.4)^2 cm^2 </span>
<span> A = 779.76 cm^2 </span>
Answer:
(a) 1560 W
(b) 576 W
(c) 1.01
Explanation:
Voltage, V = 120 V
Current in dryer, I = 13 A
current in vacuum cleaner, i' = 4.8 A
(a) Power consumed by dryer,
P = V I = 120 x 13 = 1560 W
(b) Power consumed by vacuum cleaner
P' = V I' = 120 x 4.8 = 576 W
(c) Energy consumed by dryer
E = P x t = 1560 x 15 x 60 = 1404000 J
Energy consumed by the vacuum cleaner
E' = P' x t' = 576 x 40 x 60 = 1382400 J
the ratio of energies is
E : E' = 1404000 : 1382400 = 1.01