V = d/t = 10m / 5 s = 2m/s
point a to point b = 2m/s
point b to point a = 2m/s
avg speed = (2m/s+2m/s)/2 = 2m/s
avg velocity= (2m/s+2m/s)/2 = 2m/s
Answer:
60N
Explanation:
force = mass * acceleration
force = 12 * 5
force =60N
Answer:
The combined momentum will be 2 units.
Explanation:
Here a piece of putty moving with 2 units of momentum strikes and sticks to a heavy bowling ball that is initially at rest. After the putty sticks to the ball, both are set in motion with a combined momentum. It is a case of inelastic collision in which the momentum of the system remains conserved.
The law of conservation of momentum will be followed here. So, the combined momentum after collision will be same as the initial momentum. Hence, the correct option is (b) "2 units".
Answer:
(a). The resultant of these forces is 1216.55 N.
(b). The direction of the resultant forces is 80.53°.
Explanation:
Given that,
First force = 1200 N
Second force = 200 N
(a). We need to calculate the resultant of these forces
Using cosine law
Put the value into the formula
The resultant of these forces is 1216.55 N.
(b). We need to calculate the direction of the resultant forces
Using formula of direction
Put the value into the formula
Hence, (a). The resultant of these forces is 1216.55 N.
(b). The direction of the resultant forces is 80.53°.
Answer:
-8 m/s²
Explanation:
Initial velocity = 40 m/s
Final velocity = 0 m/s
Time (T1) = 5 s
Time (T2) = 10 s
Acceleration = v - u/t2 - t1
Acceleration = 0 - 40/10 - 5
Acceleration = -40/5
Acceleration = -8 m/s²