The spider is traveling in a circle with radius = 15cm
The circumference of any circle = <em>2 pi (radius)</em>
The circumference of the spider's path = 2 pi (15 cm) = 30 pi cm
The spider completes a trip around this path 78 times per minute.
Its speed, relative to you, is
(78) x (30 pi) cm/min =
2,340 pi cm/min = 7,351.33 cm/min =
<em> 73.5133 meter/min =</em>
<em>4.411 km/hr =</em>
<em>2.74 miles/hour
</em>(After the last appearance of pi,
all numbers are rounded.)<em>
</em>
Answer:
1 Newton
Explanation:
F=9*10^9*q0q1/r^2]]
F=9*10^9*(q0q1)/ r^2
r=3cm
F=4N
F=9*10^9*(q0q1)/3^2
4=9*10^9*(q0q1)/9
4=10^9 q0q1
q0q1=4/10^9
q0q1=4*10^-9
To calculate the force between the forces at a distance of 6 cm
F=9*10^9*(q0q1)/ r^2
=9*10^9*(4*10^-9)/6^2
=9*10^9*(4*10^-9)/36
=10^9*4*10^-9/4
=10^9*10^-9
=1 Newton
Answer:
4.5sec
Explanation:
From the question above, the following are the parameters that are given
u= 30m/s
v= 50m/s
s= 180m
First of all we have to find the acceleration by using the third equation of motion
V^2= U^2 + 2as
50^2= 30^2 + 2(a)(180)
2500= 900 + 360a
Collect the like terms
2500-900= 360a
1600=360a
Divide both sides by the coefficient of a which is 360
1600/360=360a/360
a= 4.44m/s
The next step is to find the time. To do this we will have to use the first equation of motion
v= u + at
50= 30 + 4.44t
Collect the like terms
50-30= 4.44t
20= 4.44t
Divide both sides by the coefficient of t which is 4.44
20/4.44= 4.44t/4.44
t= 4.5sec
Hence 4.5secs elapses while the auto moves at a distance of 180m
Answer:
unequal
Explanation:
White light is a combination of all colors in the color spectrum.
Answer:
"A pendulum swinging back and forth" is an example of harmonic motion
X = Xo cos ω t
Explains the back and forth motion of the pendulum
