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sergeinik [125]
3 years ago
11

How many moles of solute are contained in a 250.0ml solution with a concentration of 2.5m

Chemistry
1 answer:
anzhelika [568]3 years ago
5 0
Mole solute=Molar concentration(mol/L)*Volume solution(L)

250.0 mL=0.2500L
2.5M=2.5 mol/L
mole solute=2.5 mol/L*0.2500L= 0.625 ≈ 0.63 mol
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sattari [20]

Answer:

Step 1;

q = w = -0.52571 kJ, ΔS = 0.876 J/K

Step 2

q = 0, w = ΔU = -7.5 kJ, ΔH = -5.00574 kJ

Explanation:

The given parameters are;

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Step 1

For isothermal expansion, we have;

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w = n·R·T·ln(P_f/P_i) = 1 × 8.314 × 600.15 × ln(90/100) = -525.71

w ≈<em> -0.52571</em> kJ

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Step 2

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ΔU = 25×(27 - 327) = -7,500

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ΔH = ΔU = <em>-5.00574 kJ</em>

6 0
2 years ago
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snow_lady [41]

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3 years ago
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Answer:

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Explanation:

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