A particle moves with a velocity v in a circle of radius r, then its angular velocity is equal
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(a). The car's average velocity between t = 1.0s to t = 1.5s will be -
(b). The car's acceleration at t = 1.5s will be -
(c). Car's speed is increasing with time.
We have a a remote controlled toy car that starts from rest and begins to accelerate in a straight line.
We have to determine -
- The car's average velocity (in m/s) in the interval between -
t = 1.0 s to t = 1.5 s.
- The car's acceleration at t = 1.5 s.
- Determining whether car's speed increasing or decreasing with time.
The rate of change of velocity with respect to time is called Acceleration. Mathematically -
According to the question, we have the following data for the Car -
t = 0s → x = 0m
t = 0.5s → x = 0.1m
t = 1.0s → x = 0.4m
t = 1.5s → x = 0.9m
t = 2.0s → x = 1.6m
PART - A
The car's average velocity between t = 1.0s to t = 1.5s will be -
PART - B
Velocity at t = 1.5 s will be -
The car's acceleration at t = 1.5s will be -
PART - C
Since, the acceleration of the car is positive, this means that the car is accelerating in the forward direction. Hence, its speed is increasing with time.
[ The following data was missing in your answer. The complete question would include this data also -
t = 0s → x = 0m
t = 0.5s → x = 0.1m
t = 1.0s → x = 0.4m
t = 1.5s → x = 0.9m
t = 2.0s → x = 1.6m ]
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The question is incomplete. The complete question is :
A platypus foraging for prey can detect an electric field as small as 0.002 N/C.
-To give an idea of sensitivity of the platypus's electric sense, how far from a +80nC point charge does the field have this magnitude?
Solution :
Given electric field, E = 0.002 N/C
Charge, Q = + 80 nC
or
R = 600 m
This is the distance of the charge from the point of observations.