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sergeinik [125]
3 years ago
5

Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant

(and quite modest) acceleration. A train travels through a congested part of town at 5.0 m/s. Once free of this area, it speeds up to 12 m/s in 8.0 s. At the edge of town, the driver again accelerates, with the same acceleration, for another 16 s to reach a higher cruising speed. What is the final speed?
Physics
1 answer:
snow_lady [41]3 years ago
3 0

Answer:

26m/s

Explanation:

Assuming that the acceleration is constant, we can start by calculating the train speed when it's free of the congested area:

a = \frac{\deltav}{\deltat} = \frac{12 - 5}{8} = \frac{7}{8} = 0.875 m/s^2

Then with the same acceleration we can find out the final speed:

v = v_0 + at = 12 + 0.875*16 = 26m/s

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E_m=E_p
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It hasn't changed! So inserting this into the equation relating the total energy at the highest point we'll have:
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4 0
3 years ago
Read 2 more answers
Bare free charges do not remain stationary when close together. To illustrate this, calculate the acceleration of two isolated p
Marta_Voda [28]

Answer:

Acceleration, a=9.91\times 10^{15}\ m/s^2

Explanation:

It is given that,

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Charge on protons, q=1.6\times 10^{-19}\ C

Mass of protons, m=1.67\times 10^{-27}\ kg

We need to find the acceleration of two isolated protons. It can be calculated by equating electric force between protons and force due to motion as :

ma=\dfrac{kq^2}{r^2}

a=\dfrac{kq^2}{mr^2}      

a=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{1.67\times 10^{-27}\times (3.73\times 10^{-9})^2}      

a=9.91\times 10^{15}\ m/s^2

So, the acceleration of two isolated protons is 9.91\times 10^{15}\ m/s^2. Hence, this is the required solution.

3 0
3 years ago
What is the symbol for angle?
zlopas [31]

Answer:

angle is denoted by /_ , see in explanation

4 0
4 years ago
What force is required to give an object with mass 2000 kg an acceleration of 3.5 m/s2
ch4aika [34]
According to Newton's Second Law:
F = m*a = 2000 kg*3.5 m/s^2 = 7000 N
8 0
4 years ago
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A helicopter, starting from rest, accelerates straight up from the roof of a hospital. The lifting force does work in raising th
Whitepunk [10]

Answer:

24.3KW

Explanation:

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The kinetic energy is increasing as the body gain speed, the potential energy also increases as the body gain height against gravity and the chemical energy in form of fuel decreases as the body burn the fuel to create a lifting force

B) The workdone by the lifting force = the change in kinetic energy + the change in potential energy

C)The time taken in seconds to do the work is the variable needed

D) average power generated by the lifting force = (change in kinetic energy + change in potential energy) / time taken in seconds

Average power = 1/2 * m(mass) (Vf-Vi)^2 + mg(hf-hi) /t where vf is final speed and vi is initial speed at rest = 0, similarly, hf = final height and hi = initial height.

Average power = 1/2*810*7^2 + 810*9.81*8.2/3.5s

Average power = (19845+65158.02)/3.5 = 24286.577 approx 24.3kW

5 0
3 years ago
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