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garik1379 [7]
2 years ago
7

Measurements show that enthalpy of a mixture of gaseous reactants decreases by 228. kJ during a certain chemical reaction, which

is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that -55kJ of work is done on the mixture during the reaction.
Calculate the change in energy of the gas mixture during the reaction.

Is the reaction exothermic or endothermic?
Chemistry
2 answers:
Tcecarenko [31]2 years ago
7 0
Total change in energy = Heat produced by system + work done on the system
= 228 - 55
= 173 kJ

Because this energy is released as heat, the reaction is exothermic.
Montano1993 [528]2 years ago
7 0

Answer:

-283 KJ, exothermic

Explanation:

We are given that

Enthalpy of a mixture of a gases reactants

Change in enthalpy=\Delat H=-228 KJ

Where negative sign represents the enthalpy decreases.

Pressure=Constant.

Work don=w=-55 KJ

We have to calculate the change in energy of the gas mixture during the reaction.

At constant pressure, the change in enthalpy

\Delta H=\Delta U+P\Delta V

Where w=-P\Delta V

Where P=Constant

\Delta V= Change in volume

\Delta U= Change in energy

\Delta U=\Delta H-P\Delta V

\Delta U=\Delta H+w

Substitute the values then we get

\Delta U=-228-55=-283 KJ

Hence, the change in energy of the gas mixture during the reaction=-283 KJ

Change in enthalpy is negative it means the reaction is exothermic because the energy is evolved.

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