Answer:
option c. 21.0
Explanation:
It was given that to find 3 significant figures. So the answer is 21.0
Answer:
the moment of inertia with the arms extended is Io and when the arms are lowered the moment
I₀/I > 1 ⇒ w > w₀
Explanation:
The angular momentum is conserved if the external torques in the system are zero, this is achieved because the friction with the ice is very small,
L₀ = L_f
I₀ w₀ = I w
w = w₀
where we see that the angular velocity changes according to the relation of the angular moments, if we approximate the body as a cylinder with two point charges, weight of the arms
I₀ = I_cylinder + 2 m r²
where r is the distance from the center of mass of the arms to the axis of rotation, the moment of inertia of the cylinder does not change, therefore changing the distance of the arms changes the moment of inertia.
If we say that the moment of inertia with the arms extended is Io and when the arms are lowered the moment will be
I <I₀
I₀/I > 1 ⇒ w > w₀
therefore the angular velocity (rotations) must increase
in this way the skater can adjust his spin speed to the musician.
Answer:
Vf = 4.40 m/s and θ = 88º
Explanation:
To solve this problem, let's look for the resultants of the force and with this we calculate the accelerations in each axis.
Let's use trigonometry to break down the forces
Sin 25 = F1x / F1
Cos 25 = F1y / F1
Fix = F1 sin 25
F1x = 1.85 sin 25
F1x = 0.78 N
F1y = 1.85 cos 25
F1y = 1.67 N
F2 = - 0.782 N j ^ (south)
F3 = - 0.750 N i ^ (west)
We write Newton's second law
X axis (East-West)
F1x - F3 = m ax
ax = (F1x - F3) / m
ax = (0.78 - (0.750)) / 0.325
ax = 0.092 m / s²
Y axis (North-South)
F1y - F2 = m ay
ay = (1.67- (0.782)) / 0.325
ay = 2.73 m / s²
Let's calculate the magnitude and direction of the acceleration
a = RA ax2 + ay2
a = RA 0.092² + 2.73²
a = 2.73m / s²
tan θ = ay / ax
θ = tan⁻¹ (2.73/0.092)
θ = tan⁻¹ 29.67
θ = 88º
We calculate the speed, notice that we use the total acceleration to be able to use the totol displacement
Vf² = vo² + 2 at D
Vf² = 0 + 2 2.73 3.55
Vf = √ 19.38
Vf = 4.40 m / s
θ = 88º
Answer:
B
Explanation:
In a common rail system, the fuel is distributed to the injectors from the rail where there is high pressure accumulation.High pressure fuel pump feds the rail and with the help of the start and end signals the injector is activated.For example in diesel common rail direct injection systems, the rail is connected to injectors using individual pipes in that the injectors work hand in hand with the fuel pump which ensures fuel injection timing and amount. Comparing this with early models, the fuel pump was responsible for timing, quantity and pressure.So power stroke in a modern common rail system does not only rely on single injection of pump but also has multiple injection events during combution process.
Explanation:
the correct answer is Option 5.√½gh.
hope this helps you.