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Molodets [167]
3 years ago
7

At the end of the Shock Wave roller coaster ride, the 6000-kg train of cars (includes passengers) is allowed from a speed of 20

m/s to a speed of 5 m/s over a distance of 20 meters. Determine the braking force required to slow the train of cars by this amount.
Physics
1 answer:
Angelina_Jolie [31]3 years ago
6 0

Answer:

56250 N

Explanation:

mass, m = 6000 kg

initial speed, u = 20 m/s

final speed, v = 5 m/s

distance, s = 20 m

Use third equation of motion

v^{2}=u^{2}+2as

5 x 5 = 20 x 20 + 2 a x 20

25 = 400 + 40 a

a = - 9.375 m/s^2

Braking force, F = mass x acceleration

F = 6000 x 9.375

F = 56250 N

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A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. ten second later, he is moving at 15 m/s. what is his
boyakko [2]

Answer:

1 m/s²

Explanation:

From the question,

Using

a = (v-u)/t.................... Equation 1

Where a = accelartion of the bicycle, v = Final velocity, u = initial velocity, t = time.

Given: v = 15 m/s, u = 5 m/s, t = 10 s

Substitute these values into equation 1

a = (15-5)/10

a = 10/10

a = 1 m/s²

Hence the acceleration of the bicycle is 1 m/s²

6 0
3 years ago
What is the difference between gross anatomy and microscopic anatomy?
Maurinko [17]
There are two major types of anatomy. Gross (macroscopic) anatomy is the study of anatomical structures that can be seen by the eye, such as the external and internal bodily organs. Microscopic anatomy is the study of tiny anatomical structures such as tissues and cells.
5 0
3 years ago
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An object has a constant velocity of 20 m/s to the north, and there are two forces acting on it. What is this situation called
Llana [10]

When an object move with a constant velocity and there are forces acting on it, this is called unbalanced force. The forces acting on an object is a net force, which is capable of changing speed and/or direction of motion of an object. However, the two forces acting on the object can be added together to give the resultant force, which is a single force that has the same effect on the object as all the individual forces acting together.

5 0
3 years ago
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How many excess electrons must be distributed uniformly within the volume of an isolated plastic sphere 25.0 cm in diameter to p
katrin [286]

Answer:

Required charge q=2.6\times 10^{9}C.

n=1.622\times 10^{10}\ electrons

Explanation:

Given:

Diameter of the isolated plastic sphere = 25.0 cm

Magnitude of the Electric field = 1500 N/C

now

Electric field (E) is given as:

E =\frac{kq}{r^2}

where,

k = coulomb's constant = 9 × 10⁹ N

q = required charge

r = distance of the point from the charge where electric field is being measured

The value of r at the just outside of the sphere = \frac{25.0}{2}=12.5cm=0.125m

thus, according to the given data

1500N/C=\frac{9\times 10^{9}N\times q}{(0.125m)^2}

or

q=\frac{0.125^2\times 1500}{9\times 10^{9}}

or

Required charge q=2.6\times 10^{9}C.

Now,

the number of electrons (n) required will be

n=\frac{required\ charge}{charge\ of\ electron}

or

n=\frac{2.6\times 10^{-9}}{1.602\times 10^{-19}}

or

n=1.622\times 10^{10}\ electrons

6 0
4 years ago
Give an example of a measurement that is precise to the nearest tenth of a gram.
Svet_ta [14]

Answer:

So we have a measure in grams, we can start with something like:

143.523 grams.

Now we want this measurement to be precise to the nearest tenth of a gram.

The nearest tenth of a gram is the first digit after the decimal point, then the digits that come after this are not useful, because they are outside our precision range.

Then we must write our measurement as:

143.5 grams

Where the digit that came after the 5 was a 2, so we rounded down.

4 0
3 years ago
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