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Allisa [31]
3 years ago
9

Block A, with a mass of 4.0 kg, is moving with a speed of 3.0 m/s while block B, with a mass of 6.0 kg, is moving in the opposit

e direction with a speed of 5.0 m/s. What is the momentum of the two-block system
Physics
1 answer:
ElenaW [278]3 years ago
5 0

Answer:

The momentum of the two-block system is 18 kg-m/s

Explanation:

It is given that,

Mass of block A, m_A=4\ kg  

Mass of block B, m_B=6\ kg  

Velocity of block A, v_A=3\ m/s  

Velocity of block B, v_B=-5\ m/s (it is moving in opposite direction)

We need to find the momentum of two block system. It is given by the product of mass and velocity for both blocks i.e.

p=m_Av_A+m_Bv_B

p=4\ kg\times 3\ m/s+6\ kg\times (-5\ m/s)

p = -18 kg-m/s

So, the momentum of two block system is 18 kg-m/s. Hence, this is the required solution.                                            

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Answer:

Hey mate I shall not tell you the answer I shall explain it to you after this if still you can't understand then say

Explanation:

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3 years ago
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777dan777 [17]
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3 years ago
A proton orbits a long charged wire, making 1.80 ×106 revolutions per second. The radius of the orbit is 1.20 cm What is the wir
Fantom [35]

Answer:

linear charge density = -9.495 × 10^{-34} C/m

Explanation:

given data

revolutions per second = 1.80 × 10^{6}

radius = 1.20 cm

solution

we know that when proton to revolve around charge wire then centripetal force is require to be in orbit of radius around provide by electric force

so

- q × E = m × w² × r     ..................1

- 9 × 10^{9}  × \frac{2*linear\ charge\ density}r} q =  m × w² × r   ............2

and w = \frac{2*\pi}{T}  

w = \frac{d\theta }{dt}

w = 1.80 × 10^{6} × \frac{2*\pi}{1}

w = 11304000 rad/s

so here from equation 2

- 9 × 10^{9}  × \frac{2*linear\ charge\ density}{0.012} 1.80 × 10^{6} =  1.672 × 10^{-27} × 11304000² × 0.0120  

linear charge density = -9.495 × 10^{-34} C/m

8 0
3 years ago
A pitcher can throw a fastball that reaches home plate at 95 mph. What is this speed in m/s
Taya2010 [7]
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How long must a simple pendulum be if it is to make exactly one swing per four seconds? (That is, one complete oscillation takes
cricket20 [7]

Answer:

Length of the pendulum will be 3.987 m

Explanation:

We have given time period of the pendulum T = 8 sec

Acceleration due to gravity g=9.81m/sec^2

We have to find the length of the simple pendulum

We know that time period of the simple pendulum is given by

T=2\pi \sqrt{\frac{l}{g}}

8=2\times 3.14 \sqrt{\frac{l}{9.81}}

l=3.987m

So length of the pendulum will be 3.987 m

3 0
3 years ago
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