1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Allisa [31]
3 years ago
9

Block A, with a mass of 4.0 kg, is moving with a speed of 3.0 m/s while block B, with a mass of 6.0 kg, is moving in the opposit

e direction with a speed of 5.0 m/s. What is the momentum of the two-block system
Physics
1 answer:
ElenaW [278]3 years ago
5 0

Answer:

The momentum of the two-block system is 18 kg-m/s

Explanation:

It is given that,

Mass of block A, m_A=4\ kg  

Mass of block B, m_B=6\ kg  

Velocity of block A, v_A=3\ m/s  

Velocity of block B, v_B=-5\ m/s (it is moving in opposite direction)

We need to find the momentum of two block system. It is given by the product of mass and velocity for both blocks i.e.

p=m_Av_A+m_Bv_B

p=4\ kg\times 3\ m/s+6\ kg\times (-5\ m/s)

p = -18 kg-m/s

So, the momentum of two block system is 18 kg-m/s. Hence, this is the required solution.                                            

You might be interested in
If you are sitting in a bus that is traveling along a straight, level road at 100 km/hr., you are traveling at 100 km/hr too. (a
aleksandr82 [10.1K]

Answer:

hhhhhhhhhhhhhhhhhhhhhhhhhhhh

Explanation:

hhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

8 0
3 years ago
What is the Law of Conservation of Mass and Energy. Fist answer gets brainliest!!←←←←
anzhelika [568]

Answer:The amount if mass of all substances before or after a chemical change are equal

Explanation:

4 0
3 years ago
Read 2 more answers
What is the car's average velocity (in m/s) in the interval between t = 1.0 s<br> to t = 1.5 s?
natali 33 [55]

Answer:

1.4 m/s

Explanation:

From the question given above, we obtained the following data:

Initial Displacement (d1) = 0.9 m

Final Displacement (d2) = 1.6 m

Initial time (t1) = 1.5 secs

Final time (t2) = 2 secs

Velocity (v) =..?

The velocity of an object can be defined as the rate of change of the displacement of the object with time. Mathematically, it can be expressed as follow:

Velocity = change of displacement /time

v = Δd / Δt

Thus, with the above formula, we can obtain the velocity of the car as follow:

Initial Displacement (d1) = 0.9 m

Final Displacement (d2) = 1.6 m

Change in displacement (Δd) = d2 – d1 = 1.6 – 0.9

= 0.7 m

Initial time (t1) = 1.5 secs

Final time (t2) = 2 secs

Change in time (Δt) = t2 – t1

= 2 – 1.5

= 0.5 s

Velocity (v) =..?

v = Δd / Δt

v = 0.7/0.5

v = 1.4 m/s

Therefore, the velocity of the car is 1.4 m/s

4 0
3 years ago
A mole of ideal gas expands at T=27 °C. The pressure changes from 20 atm to 1 atm. What’s the work that the gas has done and wha
Airida [17]

Answer:

  • The work made by the gas is 7475.69 joules
  • The heat absorbed is 7475.69 joules

Explanation:

<h3>Work</h3>

We know that the differential work made by the gas  its defined as:

dW =  P \ dv

We can solve this by integration:

\Delta W = \int\limits_{s_1}^{s_2}\,dW = \int\limits_{v_1}^{v_2} P \ dv

but, first, we need to find the dependence of Pressure with Volume. For this, we can use the ideal gas law

P \ V = \ n \ R \ T

P = \frac{\ n \ R \ T}{V}

This give us

\int\limits_{v_1}^{v_2} P \ dv = \int\limits_{v_1}^{v_2} \frac{\ n \ R \ T}{V} \ dv

As n, R and T are constants

\int\limits_{v_1}^{v_2} P \ dv = \ n \ R \ T \int\limits_{v_1}^{v_2} \frac{1}{V} \ dv

\Delta W= \ n \ R \ T  \left [ ln (V) \right ]^{v_2}_{v_1}

\Delta W = \ n \ R \ T  ( ln (v_2) - ln (v_1 )

\Delta W = \ n \ R \ T  ( ln (v_2) - ln (v_1 )

\Delta W = \ n \ R \ T  ln (\frac{v_2}{v_1})

But the volume is:

V = \frac{\ n \ R \ T}{P}

\Delta W = \ n \ R \ T  ln(\frac{\frac{\ n \ R \ T}{P_2}}{\frac{\ n \ R \ T}{P_1}} )

\Delta W = \ n \ R \ T  ln(\frac{P_1}{P_2})

Now, lets use the value from the problem.

The temperature its:

T = 27 \° C = 300.15 \ K

The ideal gas constant:

R = 8.314 \frac{m^3 \ Pa}{K \ mol}

So:

\Delta W = \ 1 mol \ 8.314 \frac{m^3 \ Pa}{K \ mol} \ 300.15 \ K  ln (\frac{20 atm}{1 atm})

\Delta W = 7475.69 joules

<h3>Heat</h3>

We know that, for an ideal gas, the energy is:

E= c_v n R T

where c_v its the internal energy of the gas. As the temperature its constant, we know that the gas must have the energy is constant.

By the first law of thermodynamics, we know

\Delta E = \Delta Q - \Delta W

where \Delta W is the Work made by the gas (please, be careful with this sign convention, its not always the same.)

So:

\Delta E = 0

\Delta Q = \Delta W

7 0
3 years ago
Reactants → products
Nat2105 [25]
The answer is A

Explanation: the conservation of matter means that the mass stays the same
4 0
3 years ago
Read 2 more answers
Other questions:
  • Why do planets not travel in a straight path?
    15·1 answer
  • Blood should not be stored in which way?
    8·2 answers
  • Why is a cathode ray tube connected to a vacuum pump?
    7·1 answer
  • _________ is affected by your brakes, tires, the road surface, and speed.
    15·1 answer
  • In a decompostion reaction, the reaction decays 21.2 times more rapidly at 22°C then at 4 °C. What is the overall activation ene
    6·1 answer
  • Who developed the first comprehensive theory of personality?
    12·2 answers
  • How many grams is 5kg of tap water?
    14·1 answer
  • Leght of a chief of a circle
    9·1 answer
  • A red shirt appears red because?
    10·2 answers
  • Eee A student conducts an investigation to determine how the force of gravity affects different objects dropped from different h
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!