Block A, with a mass of 4.0 kg, is moving with a speed of 3.0 m/s while block B, with a mass of 6.0 kg, is moving in the opposit
1 answer:
Answer:
The momentum of the two-block system is 18 kg-m/s
Explanation:
It is given that,
Mass of block A,
Mass of block B,
Velocity of block A,
Velocity of block B, (it is moving in opposite direction)
We need to find the momentum of two block system. It is given by the product of mass and velocity for both blocks i.e.
p = -18 kg-m/s
So, the momentum of two block system is 18 kg-m/s. Hence, this is the required solution.
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Answer:
(1) passed through the foil
Explanation:
Ernest Rutherford conducted an experiment using an alpha particle emitter projected towards a gold foil and the gold foil was surrounded by a fluorescent screen which glows upon being struck by an alpha particle.
- When the experiment was conducted he found that most of the alpha particles went away without any deflection (due to the empty space) glowing the fluorescent screen right at the point of from where they were emitted.
- While a few were deflected at reflex angle because they were directed towards the center of the nucleus having the net effective charge as positive.
- And some were acutely deflected due to the field effect of the positive charge of the proton inside the nucleus. All these conclusions were made based upon the spot of glow on the fluorescent screen.
