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Julli [10]
3 years ago
10

A small sphere is hung by a string from the ceiling of a van. When the van is stationary, the sphere hangs vertically. However,

when the van accelerates, the sphere swings backward so that the string makes an angle of
θ
with respect to the vertical.
(a) Derive an expression for the magnitude a of the acceleration of the van in terms of the angle
θ
and the magnitude g of the acceleration due to gravity.
(b) Find the acceleration of the van when
θ=10.0∘
(c) What is the angle
θ
when the van moves with a constant velocity?
Physics
1 answer:
olganol [36]3 years ago
3 0

Answer with Explanation:

We are given that

String makes an angle w.r.t  vertical=\theta=

a.We have to derive an expression for the magnitude of the acceleration of the van in terms of the angle \theta and magnitude g of the acceleration due to gravity.

According to newton's second law

T sin\theta=ma

Tcos\theta=mg

\frac{Tsin\theta}{Tcos\theta}=\frac{ma}{mg}

tan\theta=\frac{a}{g}

a=gtan\theta

b.\theta=10^{\circ}

g=9.8 m/s^2

a=9.8\times tan10^{\circ}=1.73 m/s^2

c.Velocity=Constant

We have to find the angle \theta

a=0

0=9.8tan\theta

tan\theta=0

tan\theta=tan0

\theta=0^{\circ}

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