Question

The coordinate plane below shows the path of a bicyclist. Each square represents 10 meters.

Answer 1

Part A)

As we know see the graph

It travel from point A to G

so the displacement is from A to G directly

its 10 m towards North

Part B)

total distance we have to calculate total path length

so from A to B = 2 squares

from B to C = 4 squares

C to D = 1 square

D to E = 5 square

E to F = 1 square

F to G = 4 square

total distance = 2 + 4 + 1 + 5 + 1 + 4 = 17 square

1 square = 10 m

total distance = 170 m

PART C)

As we know that average speed is defined as

$v_{avg} = \frac{total distance}{total time}$

as we know that

total time = 45 s

total distance = 170 m

from above formula now

$v = \frac{170}{45} = 3.78 m/s$

PART D)

As we know that average velocity is defined as

$v_{avg} = \frac{displacement}{time}$

here we have

displacement = 10 m north

time = 45 s

now from above equation

$v_{avg} = \frac{10}{45} = 0.22 m/s$

Part E)

As we know that average acceleration is rate of change in the velocity

so here we have

final velocity = 3 m/s

initial velocity = 4 m/s

time = 3 s

now from the equation

$a = \frac{v_f - v_i}{t}$

$a = \frac{3 - 4}{3} = -0.33 m/s^2$